如何制作 Parse.Query.AND?

The result of the .find is all the objects with User = Parse.User.current()) and all the objects with Deseo = artist but I want the objects with the two queries together:

User = Parse.User.current()) 和 Deseo = 艺术家

推荐答案

您实际上已经正确设置了它以执行 AND 查询.问题(假设您的数据结构设置正确)是您的 User 字段是指向 User 表的指针.因此，您需要查询一个等于指针的用户，而不是一个等于 Parse.User.current() 的用户，后者将返回一个字符串.类似于以下内容:

You've actually got it setup correctly to do an AND query. The problem (assuming that your data structure is setup properly) is that your User field is a Pointer to the User table. Therefore, you need to query for a User equal to the pointer, as opposed to a User equal to Parse.User.current() which will return a string. Something like the following:

var userPointer = {
  __type:    'Pointer',
  className: 'User',
  objectId:  Parse.User.current().id
}

queryDeseo1.equalTo('User', userPointer);

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