根据多个条件格式化 pandas 数据框中单元格的颜色

问题描述

我正在尝试格式化数据框中特定列的单元格的颜色，但我无法根据多种条件来做到这一点.

这是我的数据框 (df):

 姓名 ID Cel 日期0 迭戈 b000000005 7878 2565-05-31 20:53:001 路易斯 b000000015 6464 2017-05-11 20:53:002 维达尔 b000000002 1100 2017-05-08 20:53:003 约翰 b000000011 4545 2017-06-06 20:53:004 优素福 b000000013 1717 2017-06-06 20:53:00

我希望日期"列中的值根据以下条件改变颜色:

 如果日期 <日期时间.now():颜色='绿色'删除日期>日期时间.now():日期 = '黄色'删除日期>(datetime.now() + timedelta(days=60)):颜色='红色'

这是我当前的代码:

定义颜色(val):如果 val <日期时间.now():颜色='绿色'elif val >日期时间.now():颜色='黄色'elif val >(datetime.now() + timedelta(days=60)):颜色='红色'返回'背景颜色:％s'％颜色df.style.apply(颜色，子集 = ['Fecha'])

我收到以下错误:

ValueError: ('一个Series的真值不明确.使用a.empty、a.bool()、a.item()、a.any()或a.all().','发生在索引 Fecha')

输出是:

Out[65]: <pandas.formats.style.Styler at 0x1e3ab8dec50>

任何帮助将不胜感激.

使用

Jupyter 笔记本的屏幕截图.如果您改为 print 输出，您将获得对 Styler 对象的引用:

print(df.style.applymap(color, subset=['Date']))<pandas.formats.style.Styler 对象位于 0x116db43d0>

I am trying to format the color of a cell of an specific column in a data frame, but I can't manage to do it according to multiple conditions.

This is my dataframe (df):

    Name     ID         Cel     Date
0   Diego   b000000005  7878    2565-05-31 20:53:00
1   Luis    b000000015  6464    2017-05-11 20:53:00
2   Vidal   b000000002  1100    2017-05-08 20:53:00
3   John    b000000011  4545    2017-06-06 20:53:00
4   Yusef   b000000013  1717    2017-06-06 20:53:00

I want the values in the "Date" column to change color according to the following conditions:

 if date < datetime.now():
        color = 'green'
    elif date > datetime.now():
        date = 'yellow'
    elif date > (datetime.now() + timedelta(days=60)):
        color = 'red'

This is my current code:

def color(val):
    if val < datetime.now():
        color = 'green'
    elif val > datetime.now():
        color = 'yellow'
    elif val > (datetime.now() + timedelta(days=60)):
        color = 'red'
    return 'background-color: %s' % color

df.style.apply(color, subset = ['Fecha'])

I am getting the following error:

ValueError: ('The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().', 'occurred at index Fecha')

The output is:

Out[65]: <pandas.formats.style.Styler at 0x1e3ab8dec50>

Any help will be appreciated.

Use applymap:

from datetime import datetime, timedelta
import pandas as pd

name = ['Diego', 'Luis', 'Vidal', 'John', 'Yusef']
id = ['b000000005', 'b000000015', 'b000000002', 'b000000011', 'b000000013']
cel = [7878, 6464, 1100, 4545, 1717]
date = pd.to_datetime(['2017-05-31 20:53:00', '2017-05-11 20:53:00', '2017-05-08 20:53:00', 
                       '2017-06-06 20:53:00', '2017-06-06 20:53:00'])

df = pd.DataFrame({'Name':name,'ID':id,'Cel':cel,'Date':date})

def color(val):
    if val < datetime.now():
        color = 'green'
    elif val > datetime.now():
        color = 'yellow'
    elif val > (datetime.now() + timedelta(days=60)):
        color = 'red'
    return 'background-color: %s' % color

df.style.applymap(color, subset=['Date'])

Screenshot from Jupyter notebook. If you print the output instead, you'll just get a reference to the Styler object:

print(df.style.applymap(color, subset=['Date']))
<pandas.formats.style.Styler object at 0x116db43d0>

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