>>> import os
>>> os.chdir('c:/python27')
>>> os.listdir('c:')
['Tools', 'include', 'python.exe', 'libs', 'DLLs', 'Lib', 'NEWS.txt',
'w9xpopen.exe', 'Doc', 'pythonw.exe', 'LICENSE.txt', 'README.txt', 'tcl']
>>> os.listdir('c:/')
['users', 'Program Files', 'Python27', 'windows']
为什么c:"后面的/"会影响结果?有没有办法让 os.listdir('c:')
返回 "c:/" 的内容?
Why is the "/" after "c:" affecting the outcome? Is there a way to get os.listdir('c:')
to return the contents of "c:/"?
这不是 Python 特有的,它本质上是一个 Windows 问题.
This is not specific to Python, it's a Windows question at heart.
在 Windows 中,C:
和 C:
(或者,C:/
)具有完全不同的含义:
In Windows C:
and C:
(or, alternatively C:/
) have quite different meanings:
C:
指的是驱动器上的当前目录C:
C:
(和C:/
)指的是驱动器的根目录C:
C:
refers to the current directory on the drive C:
C:
(and C:/
) refers to the root directory of the drive C:
虽然类 UNIX 操作系统只有一个当前目录",但 Windows 有两个独立的概念:
While UNIX-like operating systems simply have a "current directory", Windows has two separate notions:
所以当前驱动器可以是D:
,C:
上的当前目录可以是Windows
(实际上是C:Windows
)和 D:
上的当前目录可能是 Data
(实际上是 D:Data
).在这种情况下,解决方案的工作方式如下:
So the current drive could be D:
, the current directory on C:
could be Windows
(effectively C:Windows
) and the current directory on D:
could be Data
(effectively D:Data
). In this scenario resolution would work like this:
.
将引用 D:Data
将引用 D:
C:
将引用 C:Windows
C:Foo
将引用 C:Foo
.
would refer to D:Data
would refer to D:
C:
would refer to C:Windows
C:Foo
would refer to C:Foo
因此,如果您想获得有关特定目录的信息,则应始终使用完整路径包括驱动器和目录,如 C:
.
So if you want to have information about a specific directory, you should always use a full path including both a drive and a directory, such as C:
.
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