问题描述
假设我有一个这样的 Python 列表:
Say I have a Python list like this:
我想在每个第 n 个元素之后插入一个x",比如说该列表中的三个字符.结果应该是:
I want to insert an 'x' after every nth element, let's say three characters in that list. The result should be:
我知道我可以通过循环和插入来做到这一点.我真正在寻找的是一种 Python 方式,也许是单线?
I understand that I can do that with looping and inserting. What I'm actually looking for is a Pythonish-way, a one-liner maybe?
推荐答案
我有两个一体机.
给定:
使用
enumerate
获取索引,每3rd个字母添加'x'
,eg:mod(n, 3) == 2
,然后拼接成字符串并list()
.
Use
enumerate
to get index, add'x'
every 3rd letter, eg:mod(n, 3) == 2
, then concatenate into string andlist()
it.
但是作为 @sancho.s 指出如果任何元素有多个字母,这将不起作用.
But as @sancho.s points out this doesn't work if any of the elements have more than one letter.
使用嵌套推导来展平列表列表(a),以 3 个为一组进行切片,如果距离末尾小于 3,则添加 'x'
列表.
Use nested comprehensions to flatten a list of lists(a), sliced in groups of 3 with 'x'
added if less than 3 from end of list.
(a) [item for subgroup in groups for item in subgroup]
展平一个锯齿状的列表列表.
(a) [item for subgroup in groups for item in subgroup]
flattens a jagged list of lists.
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