遍历指针向量

问题描述

我正在尝试遍历玩家手中的牌.

I'm trying to iterate through a Players hand of cards.

#include <vector>
#include <iostream>

class Card {
  int card_colour, card_type;
public:
  std::string display_card();
};

std::string Card::display_card(){
  std::stringstream s_card_details;
  s_card_details << "Colour: " << card_colour << "
";
  s_card_details << "Type: " << card_type << "
";
    
  return s_card_details.str();
}

int main() 
{
  std::vector<Card*>current_cards;
  vector<Card*>::iterator iter;
  for(iter = current_cards.begin(); iter != current_cards.end(); iter++) 
  {
    std::cout << iter->display_card() << std::endl;
  }
}

这一行

std::cout << iter->display_card() << std::endl;

目前想出了

错误:表达式必须具有指向类的类型.

error: Expression must have pointer-to-class type.

我该如何解决这个问题?

How can I fix this?

推荐答案

试试这个:

cout << (*iter)->display_card() << endl;

* 运算符为您提供迭代器引用的项目，在您的情况下，它是一个指针.然后使用 -> 取消引用该指针.

The * operator gives you the item referenced by the iterator, which in your case is a pointer. Then you use the -> to dereference that pointer.

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