对于向量,可以假设元素连续存储在内存中,允许范围 [&vec[0], &vec[vec.capacity()) 用作正常数组.例如,
With vectors, one can assume that elements are stored contiguously in memory, allowing the range [&vec[0], &vec[vec.capacity()) to be used as a normal array. E.g.,
vector<char> buf;
buf.reserve(N);
int M = read(fd, &buf[0], N);
但现在向量不知道它包含 M 字节的数据,由 read() 从外部添加.我知道 vector::resize() 设置大小,但它也清除数据,所以它不能用于更新 read() 后的大小打电话.
But now the vector doesn't know that it contains M bytes of data, added externally by read(). I know that vector::resize() sets the size, but it also clears the data, so it can't be used to update the size after the read() call.
是否有一种简单的方法可以将数据直接读入向量并在之后更新大小?是的,我知道一些明显的解决方法,例如使用小数组作为临时读取缓冲区,并使用 vector::insert() 将其附加到向量的末尾:
Is there a trivial way to read data directly into vectors and update the size after? Yes, I know of the obvious workarounds like using a small array as a temporary read buffer, and using vector::insert() to append that to the end of the vector:
char tmp[N];
int M = read(fd, tmp, N);
buf.insert(buf.end(), tmp, tmp + M)
这行得通(这就是我今天要做的),但让我烦恼的是,如果我可以将数据直接放入其中,则不需要额外的复制操作矢量.
This works (and it's what I'm doing today), but it just bothers me that there is an extra copy operation there that would not be required if I could put the data directly into the vector.
那么,在外部添加数据时,有没有一种简单的方法可以修改矢量大小?
So, is there a simple way to modify the vector size when data has been added externally?
vector<char> buf;
buf.reserve(N);
int M = read(fd, &buf[0], N);
此代码片段调用未定义的行为.你不能写超过 size()
元素,即使你已经预留了空间.
This code fragment invokes undefined behavior. You can't write beyond than size()
elements, even if you have reserved the space.
正确的代码如下:
vector<char> buf;
buf.resize(N);
int M = read(fd, &buf[0], N);
buf.resize(M);
[&vec[0], &vec[vec.capacity())
用作普通数组"是不正确的.允许的范围是[&vec[0], &vec[vec.size())
.
[&vec[0], &vec[vec.capacity())
to be used as a normal array" isn't true. The allowable range is [&vec[0], &vec[vec.size())
.
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