这个我知道.
从 C++ 调用 C 函数:
如果我的应用程序是用 C++ 编写的,而我必须从用 C 编写的库中调用函数.那么我会使用
If my application was in C++ and I had to call functions from a library written in C. Then I would have used
//main.cpp
extern "C" void C_library_function(int x, int y);//prototype
C_library_function(2,4);// directly using it.
这不会破坏名称 C_library_function
并且链接器会在其输入的 *.lib 文件中找到相同的名称,问题就解决了.
This wouldn't mangle the name C_library_function
and linker would find the same name in its input *.lib files and problem is solved.
从 C 调用 C++ 函数???
但是在这里我要扩展一个用 C 编写的大型应用程序,我需要使用一个用 C++ 编写的库.C++ 的名称修改在这里造成了麻烦.链接器抱怨未解析的符号.好吧,我不能在我的 C 项目上使用 C++ 编译器,因为那会破坏很多其他东西.出路是什么?
But here I'm extending a large application which is written in C and I need to use a library which is written in C++. Name mangling of C++ is causing trouble here. Linker is complaining about the unresolved symbols. Well I cannot use C++ compiler over my C project because thats breaking lot of other stuff. What is the way out?
顺便说一下,我正在使用 MSVC
By the way I'm using MSVC
您需要创建一个 C API 来公开您的 C++ 代码的功能.基本上,您将需要编写声明为 extern "C" 并且具有包装 C++ 库的纯 C API(例如不使用类)的 C++ 代码.然后使用您创建的纯 C 包装器库.
You need to create a C API for exposing the functionality of your C++ code. Basically, you will need to write C++ code that is declared extern "C" and that has a pure C API (not using classes, for example) that wraps the C++ library. Then you use the pure C wrapper library that you've created.
您的 C API 可以选择遵循面向对象的风格,即使 C 不是面向对象的.例如:
Your C API can optionally follow an object-oriented style, even though C is not object-oriented. Ex:
// *.h file
// ...
#ifdef __cplusplus
#define EXTERNC extern "C"
#else
#define EXTERNC
#endif
typedef void* mylibrary_mytype_t;
EXTERNC mylibrary_mytype_t mylibrary_mytype_init();
EXTERNC void mylibrary_mytype_destroy(mylibrary_mytype_t mytype);
EXTERNC void mylibrary_mytype_doit(mylibrary_mytype_t self, int param);
#undef EXTERNC
// ...
// *.cpp file
mylibrary_mytype_t mylibrary_mytype_init() {
return new MyType;
}
void mylibrary_mytype_destroy(mylibrary_mytype_t untyped_ptr) {
MyType* typed_ptr = static_cast<MyType*>(untyped_ptr);
delete typed_ptr;
}
void mylibrary_mytype_doit(mylibrary_mytype_t untyped_self, int param) {
MyType* typed_self = static_cast<MyType*>(untyped_self);
typed_self->doIt(param);
}
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