给定以下 XML:
<users>
<user state="CA" sex="m">Max</user>
<user state="AZ" sex="f">Jen</user>
<user state="OR" sex="f">Kim</user>
<user state="NV" sex="m">Bob</user>
<user state="CA" sex="m">Jon</user>
<user state="AZ" sex="m">Jim</user>
<user state="OR" sex="f">Joy</user>
<user state="NV" sex="f">Amy</user>
</users>
使用 jQuery,有没有办法选择男性用户,来自 CA 或 NV,但不使用过滤功能?说清楚,我知道
Using jQuery, is there a way to select users who are male and are either from CA or NV, but without using the filter function? To be clear, I know that
$(xml).find("user[sex='m']")
只选择男性用户,而
$(xml).find("user[state='CA'],[state='NV']")
从 CA 或 NV 中选择所有用户.但我无法在单个选择器中将它们与逻辑 AND 结合起来.
selects all users from either CA or NV. But I am not able to combine both of them with a logical AND within a single selector.
但是,使用过滤器功能,以下工作:
Using the filter function, however, the following works:
$(xml).find("user").filter(function() {
return $(this).attr('sex') == 'm' && ($(this).attr('state') == 'CA' || $(this).attr('state') == 'NV')
}).each(function() {
alert($(this).text());
});
谢谢!
试试这个:
$(xml).find("user[sex='m'][state='CA'], user[sex='m'][state='NV']")
基本上,您将 sex
和 state
属性链接在一个简单的选择器中(这将是您的逻辑与),并在每个状态重复一次(这将是你的逻辑或).
Basically you chain the sex
and state
attributes together in a single simple selector (this would be your logical AND), and repeat them once per state (and this would be your logical OR).
测试:
$(xml).find("user[sex='m'][state='CA'], user[sex='m'][state='NV']")
.each(function() {
alert($(this).text() + " - " + $(this).attr('state'));
});
输出:
Max - CA
Bob - NV
Jon - CA
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