嘿,我将如何将一个数字四舍五入到最接近 3 的倍数?
Hay, how would i go about rounded a number up the nearest multiple of 3?
即
25 would return 27
1 would return 3
0 would return 3
6 would return 6
谢谢
if(n > 0)
return Math.ceil(n/3.0) * 3;
else if( n < 0)
return Math.floor(n/3.0) * 3;
else
return 3;
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