这是 client.on('ready', async() => {...}); 下的代码片段;
:
this.MyServer = await client.guilds.fetch('MyServer ID here').catch(error => { console.log(error) });
this.MyRole = await this.Server.roles.cache.find((role) => role.name == `MyRole name here`);
this.MyChannel = await client.channels.fetch('MyChannel ID here').catch(error => { console.log(error) });
this.MyMessage = await this.RoleChannel.messages.fetch('MyMessage ID here').catch(error => { console.log(error) });
this.MyEmojiReaction = await this.MyMessage.reactions.cache.get('MyEmoji ID here');
this.ReactingUsers = await this.MyEmojiReaction.users.fetch();
this.ReactingUsers.each(async (user) => {
if (!this.MyServer.members.cache.get(user.id)) return;
if (!user.bot) {
try {
const member = await this.MyMessage.guild.members.fetch(user.id);
member.roles.add(this.MyRole);
} catch (error) {
console.log(error);
return;
}
}
});
当机器人启动时,它应该检查反应,消息中的 this.MyEmojiReaction
,频道中的 this.MyMessage
,this.MyChannel
,并将 this.ReactingUsers
中存储的响应用户添加到角色 this.MyRole
.除了一个问题外,它基本上工作正常.
As the bot starts, it should check for the reaction, this.MyEmojiReaction
in the message, this.MyMessage
in the channel, this.MyChannel
, and add the reacting users stored in this.ReactingUsers
to the role, this.MyRole
. It is working mostly fine except one problem.
第一行if (!this.MyServer.members.cache.get(user.id)) return;
in this.ReactingMembers.each(async (user) =>如果来自
负责从函数返回, this.ReactingMembers
的用户不存在于 this.MyServer
中,{..}this.ReactingMembers
中的下一个用户永远不会执行该函数,可能是因为它从整个循环中返回.我想为下一个用户继续循环.
The first line if (!this.MyServer.members.cache.get(user.id)) return;
in this.ReactingMembers.each(async (user) => {..}
is responsible to return from the function if the user from this.ReactingMembers
is not present in this.MyServer
and it does but as it returns, the function never executes for the next users in this.ReactingMembers
, maybe because it returns from the entire loop. I want to continue the loop for the next users.
如果我理解正确,你应该使用 继续
.
If i understand it correctly, you should use continue
.
它将转而进入下一次迭代,以及数组中的下一个用户.
It will instead go to the next iteration, and the next User in the array.
在你的情况下,而不是这个:
In your case, instead of this:
if (!this.MyServer.members.cache.get(user.id)) return;
你应该这样做:
if (!this.MyServer.members.cache.has(user.id)) continue;
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