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        如何使用 discord.py 事件处理程序 on_voice_state_upd

        How to use discord.py event handler on_voice_state_update to run only when a user joins a voice channel(如何使用 discord.py 事件处理程序 on_voice_state_update 仅在用户加入语音频道时运行) - IT屋-程序员软件开发技术
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                  本文介绍了如何使用 discord.py 事件处理程序 on_voice_state_update 仅在用户加入语音频道时运行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

                  问题描述

                  我正在尝试学习如何通过 discord.py 制作一个不和谐的机器人,并希望添加一个功能,即每当另一个用户加入机器人的语音频道时,都会从机器人发送消息目前在.我不知道如何使用事件处理程序本身,也没有充分了解他们的文档来使用它.

                  I am trying to learn how to make a discord bot through discord.py and wanted to add a feature where a message would be sent from the bot whenever another user joined the voice channel that the bot is currently in. I do not know how to use the event handler itself and didn't understand their documentation enough to utilize it.

                  from discord.ext.commands import Bot 
                  client = Bot(command_prefix="!")
                  
                  @client.event
                  async def on_voice_state_update(before, after):
                      await client.say("Howdy")
                  

                  根据我对文档的有限理解,只要用户静音、耳聋、离开或加入频道,就应该使用事件处理程序.

                  From my limited understanding of the documentation, the event handler should be used whenever a user is muted, deafened, leaves, or joins a channel.

                  但是,即使我试图让它识别这些操作,它也会给我一个错误消息:

                  However, even when I tried to get it to recognize those actions it gave me an error message of:

                  Ignoring exception in on_voice_state_update
                  Traceback (most recent call last):
                    File "C:UsersSamPycharmProjectsFunBotProjectvenvlibsite-packagesdiscordclient.py", line 307, in _run_event
                      yield from getattr(self, event)(*args, **kwargs)
                    File "C:/Users/Sam/PycharmProjects/FunBotProject/my_bot2.py", line 63, in on_voice_state_update
                      await client.say("Xd ")
                    File "C:UsersSamPycharmProjectsFunBotProjectvenvlibsite-packagesdiscordextcommandsot.py", line 309, in _augmented_msg
                      msg = yield from coro
                    File "C:UsersSamPycharmProjectsFunBotProjectvenvlibsite-packagesdiscordclient.py", line 1145, in send_message
                      channel_id, guild_id = yield from self._resolve_destination(destination)
                    File "C:UsersSamPycharmProjectsFunBotProjectvenvlibsite-packagesdiscordclient.py", line 289, in _resolve_destination
                      raise InvalidArgument(fmt.format(destination))
                  discord.errors.InvalidArgument: Destination must be Channel, PrivateChannel, User, or Object. Received NoneType
                  

                  推荐答案

                  2020 年版本.请注意,我的代码在发送的消息方面表现不同.

                  A version working in 2020. Please not that my code behaves different in terms of the sent message.

                  from discord.ext.commands import Bot 
                  bot = commands.Bot(command_prefix='!')
                  
                  @bot.event
                  async def on_voice_state_update(member, before, after):
                      if before.channel is None and after.channel is not None:
                          if after.channel.id == [YOUR_CHANNEL_ID]:
                              await member.guild.system_channel.send("Alarm!")
                  

                  这篇关于如何使用 discord.py 事件处理程序 on_voice_state_update 仅在用户加入语音频道时运行的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!

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