我尝试使用以下代码,但没有成功.
I tried using the following code but it didn't work.
@bot.command()
async def avatar(ctx,*, avamember):
user = bot.get_user(avamember)
await ctx.send(f"{user.avatar_url}")
对于遇到类似问题的任何人,虽然文档中没有提到,但 discord.Member 可以将用户 ID 放在 @username 之外,因此不需要复杂的方法.
For anyone that had a similar problem, while not mentioned in the docs, discord.Member can take user ids aside from @username so there isn't any need for a complicated way.
我假设您在不和谐地使用 @UserNameHere 标记用户.将该输入作为成员对象要容易得多:)
I'm presuming you're Tagging the user with @UserNameHere in discord. It's much easier to take that input as a member Object :)
您也不需要将 url 括在引号中.
You also don't need to wrap the url in quotes.
如果它在 cog 中,则此代码:
This code is if it is in a cog:
@commands.command()
async def avatar(self, ctx, *, avamember : discord.Member=None):
userAvatarUrl = avamember.avatar_url
await ctx.send(userAvatarUrl)
此代码是否在主 bot.py 文件中:
This code is if it is in the main bot.py file:
@bot.command()
async def avatar(ctx, *, avamember : discord.Member=None):
userAvatarUrl = avamember.avatar_url
await ctx.send(userAvatarUrl)
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