如何以 Pythonic 方式向上移动 n 个目录?

问题描述

我正在寻找一种从给定目录中向上移动 n 目录的 Python 方法.

I'm looking for a pythonic way to move up n directories from a given directory.

假设我们有示例路径 /data/python_env/lib/python3.6/site-packages/matplotlib/mpl-data.如果我们要向上移动 n=2 目录，我们应该最终到达 /data/python_env/lib/python3.6/site-packages.

Let's say we have the example path /data/python_env/lib/python3.6/site-packages/matplotlib/mpl-data. If we were to move up n=2 directories we should end up at /data/python_env/lib/python3.6/site-packages.

以下工作可以向上移动 n 目录:

The following works to move up n directories:

up_n = lambda path, n: '/'.join(path.split('/')[:-n])

但是，它的可读性不是很好，并且对于 Windows 机器上的路径会失败.本质上，感觉不是一个非常pythonic的解决方案.

However, it's not very readable and fails for paths on windows machines. In essence, it doesn't feel a very pythonic solution.

是否有更好、更 Python 的解决方案，也许使用 os 模块?

Is there a better, more pythonic solution, maybe using the os module?

推荐答案

你可以使用 pathlib 标准库模块:

You can use the pathlib module of the standard library:

from pathlib import Path

path = Path('/data/python_env/lib/python3.6/site-packages/matplotlib/mpl-data')

levels_up = 2
print(path.parents[levels_up-1])
# /data/python_env/lib/python3.6/site-packages

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