背景: Trevor 正在使用标准算法的 PHP 实现:采用一组主要的默认名称-值对,并更新这些名称-值对,但仅限于那些名称-值实际存在有效更新值的对.
Background: Trevor is working with a PHP implementation of a standard algorithm: take a main set of default name-value pairs, and update those name-value pairs, but only for those name-value pairs where a valid update value actually exists.
问题:默认情况下,PHP array_merge 是这样工作的......它会用一个空值覆盖一个非空值.
Problem: by default, PHP array_merge works like this ... it will overwrite a non-blank value with a blank value.
$aamain = Array('firstname'=>'peter','age'=>'32','nation'=>'');
$update = Array('firstname' => '','lastname' => 'griffin', age =>'33','nation'=>'usa');
print_r(array_merge($aamain,$update));
/*
Array
(
[firstname] => // <-- update set this to blank, NOT COOL!
[age] => 33 // <-- update set this to 33, thats cool
[lastname] => griffin // <-- update added this key-value pair, thats cool
[nation] => usa // <-- update filled in a blank, thats cool.
)
*/
问题:在空值永远不会覆盖现有值的情况下,执行 array_merge 的最少代码行方式是什么?
Question: What's the fewest-lines-of-code way to do array_merge where blank values never overwrite already-existing values?
print_r(array_coolmerge($aamain,$update));
/*
Array
(
[firstname] => peter // <-- don't blank out a value if one already exists!
[age] => 33
[lastname] => griffin
[nation] => usa
)
*/
更新: 2016-06-17T11:51:54 更新了问题,澄清了上下文和变量重命名.
UPDATE: 2016-06-17T11:51:54 the question was updated with clarifying context and rename of variables.
array_replace_recursive($array, $array2);
这就是解决方案.
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