这是错误致命错误:调用未定义的函数assign(
这是代码,正如你所看到的,我显然已经定义了函数,为什么它不起作用
this is the error Fatal error: Call to undefined function assign(
this is the code, as you can see i obviously have defined the function so why is it not working
class shades {
function create($name, $shades, $slug, $shortDesc, $longDesc, $position){
$name = sanitize_paranoid_string($name);
$slug = slug($name);
$shortDesc = sanitize_sql_string($shortDesc);
$longDesc = sanitize_sql_string($longDesc);
$query = mysql_query("INSERT INTO products (type, name, slug, shortDesc, htmlDesc, position)VALUES('shades','$name','$slug','$shortDesc','$longDesc','$position')")or die(mysql_error());
$ID = mysql_insert_id();
assign($shades, $ID);
if($query) {return true;}
else {return false;};
}
function delassign($toID){
mysql_query("DELETE FROM assign WHERE type='shades' AND toID='$toID'")or die(mysql_error());
}
function assign($shades, $toID)
{
foreach($shades as $shade)
{
$result = mysql_query("INSERT INTO assign(type, typeID, toID)VALUES('shades','$shade','$toID')")or die(mysql_error());
if($result){echo "Added!";}
else{echo"Not Added!";}
};
}
}
您没有名为 assign() 的函数,但有一个具有此名称的方法.PHP 不是 Java,在 PHP 中你必须明确,如果你想调用一个函数
You dont have a function named assign(), but a method with this name. PHP is not Java and in PHP you have to make clear, if you want to call a function
assign()
或方法
$object->assign()
在您的情况下,对函数的调用驻留在另一个方法中.$this 总是指对象本身,其中存在一个方法.
In your case the call to the function resides inside another method. $this always refers to the object, in which a method exists, itself.
$this->assign()
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