如何在 PHP 中链接方法?

问题描述

jQuery 让我链接方法.我也记得在 PHP 中看到过同样的东西，所以我写了这个:

jQuery lets me chain methods. I also remember seeing the same in PHP so I wrote this:

class cat {
 function meow() {
 echo "meow!";
 }

function purr() {
 echo "purr!";
 }
}

$kitty = new cat;

$kitty->meow()->purr();

我无法让链条工作.它在喵喵叫之后立即产生一个致命错误.

I cannot get the chain to work. It generates a fatal error right after the meow.

推荐答案

为了回答您的 cat 示例，您的 cat 方法需要返回 $this，即当前对象实例.然后你可以链接你的方法:

To answer your cat example, your cat's methods need to return $this, which is the current object instance. Then you can chain your methods:

class cat {
 function meow() {
  echo "meow!";
  return $this;
 }

 function purr() {
  echo "purr!";
  return $this;
 }
}

现在你可以:

$kitty = new cat;
$kitty->meow()->purr();

有关该主题的真正有用的文章，请参见此处:http://www.talkphp.com/advanced-php-programming/1163-php5-method-chaining.html

For a really helpful article on the topic, see here: http://www.talkphp.com/advanced-php-programming/1163-php5-method-chaining.html

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