我有一个如下所示的 YAML 文件:
I have a YAML file that looks like this:
Main:
topofhouse:
x: 276.4375
y: 71.0
z: -60.5
yaw: -290.7768
pitch: 35.400017
2ndfloor:
x: 276.5
y: 67.0
z: -60.5
yaw: -8.626648
pitch: 16.199997
home:
x: 276.5
y: 63.0
z: -60.5
yaw: -18.976715
pitch: -32.850002
有没有办法获取Main
下的所有节点?
Is there a way to get all nodes under Main
?
获取Main
中包含的节点ID:
To get the node IDs contained in Main
:
file.getConfigurationSection("Main").getKeys(false);
输出:
Set["topofhouse", "2ndfloor", "home"]
ConfigurationSection.getConfigurationSection(String path)
方法用于获取要操作的路径.
The ConfigurationSection.getConfigurationSection(String path)
method is used to get the path on which to operate.
ConfigurationSection.getKeys(boolean deep)
方法会将当前路径中的所有节点 ID 作为 Set
获取.当 deep
设置为 true
时,它也会获取所有子节点和子子节点中的所有节点,但是它们之间的所有关系都会丢失.
The ConfigurationSection.getKeys(boolean deep)
method will get you all node IDs within the current path as a Set<String>
.
When deep
is set to true
, it will get all the nodes in the children and subchildren too, however, all relations between them will be lost.
这篇关于获取 YAML 路径下的所有节点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!