我有两张这样的桌子
wp_posts
ID post_date post_title post_type post_status
1 2020-12-10 ABC institute publish
2 2020-12-16 DEG institute publish
3 2020-12-11 XXY institute publish
4 2020-12-12 ABX institute publish
5 2020-12-24 ZYU institute publish
6 2020-12-28 ANM institute publish
7 2020-12-16 DDK institute publish
8 2020-12-30 LKI institute publish
9 2020-12-30 LKI institute publish
10 2020-12-31 LKI institute publish
11 2020-12-16 TGY institute publish
12 2020-12-16 MUN institute publish
wp_postmeta
meta_id post_id meta_key meta_value
1 1 country_id 10
2 1 registartion_by online
3 3 registartion_by offline
4 4 country_id 100
5 3 country_id 100
6 4 registartion_by online
7 5 registartion_by online
8 7 registartion_by offline
9 7 country_id 101
10 5 country_id 102
11 8 country_id 103
12 9 registartion_by online
13 8 registartion_by offline
14 9 country_id 10
15 10 country_id 104
16 10 registartion_by offline
17 11 country_id 101
18 11 registartion_by online
现在我想进行一些查询,以便最终输出应该像这样显示
Now I want to make some query so that the final output should be shown something like this
Date Country Offline_registration Online_registartion
2020-12-10 10 0 1
2020-12-11 100 1 0
2020-12-12 100 0 1
2020-12-16 101 1 1
2020-12-24 102 0 1
2020-12-30 103 0 1
2020-12-31 104 1 0
所以为了实现这一点,我做了一些这样的查询
So to achieve this I have made some query like this
SELECT date( posts.post_date ) as Date , postmeta.meta_value as Country
FROM wp_posts as posts INNER JOIN wp_postmeta as postmeta on posts.ID = postmeta.post_id WHERE posts.post_type = 'institute' AND posts.post_status = 'publish' AND postmeta.meta_key = 'country_id' GROUP BY postmeta.meta_value
但是我无法获取注册类型计数的数据,即(在线/离线注册).那么有人可以告诉我如何实现这一目标吗?
But I can't get data of registration type count i.e(online/offline registration). So can someone tell me how to achieve that?
任何建议或建议都非常值得赞赏.谢谢.
Any suggestions or advice would be really appreciable. Thanks.
您可以通过加入 wp_postmeta 两次来做到这一点,一次针对国家/地区,一次针对注册:
You can do this by joining to wp_postmeta twice, once for the country and once for the registrations:
SELECT date(p.post_date) as Date, pmc.meta_value as Country,
SUM( pmr.meta_value = 'online' ) as num_online,
SUM( pmr.meta_value = 'offline' ) as num_offline
FROM wp_posts p INNER JOIN
wp_postmeta pmc
ON pmc.post_id = p.id AND
pmc.meta_key = 'country_id' LEFT JOIN
wp_postmeta pmr
ON pmc.post_id = p.id AND
pmc.meta_key = 'registion_by'
WHERE p.post_type = 'institute' AND
p.post_status = 'publish'
GROUP BY date, country;
这篇关于MySQL查询以根据自定义列名和值获取值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
获取所有产品、类别和元数据的 SQL 查询 woocommSQL query to get all products, categories and meta data woocommerce/wordpress(获取所有产品、类别和元数据的 SQL 查询 woocommerce/wordpre
我可以在不编写 SQL 查询的情况下找出数据库列表Can I figure out a list of databases and the space used by SQL Server instances without writing SQL queries?(我可以在不编写 SQL 查询的情况下
如何创建对 SQL Server 实例的登录?How to create a login to a SQL Server instance?(如何创建对 SQL Server 实例的登录?)
如何通过注册表搜索知道SQL Server的版本和版本How to know the version and edition of SQL Server through registry search(如何通过注册表搜索知道SQL Server的版本和版本)
为什么会出现“数据类型转换错误"?使用 ExWhy do I get a quot;data type conversion errorquot; with ExecuteNonQuery()?(为什么会出现“数据类型转换错误?使用 ExecuteNonQuery()?)
如何将 DataGridView 中的图像显示到 PictureBox?How to show an image from a DataGridView to a PictureBox?(如何将 DataGridView 中的图像显示到 PictureBox?)