我见过多个示例,人们将单列汇总为逗号分隔的列表,但我还需要更多.
I've seen multiple examples of people rolling up a single column into a comma delimited list, but I need a bit more.
这是我需要的数据和结果的示例.
Here is an example of the data and results I need.
DECLARE @SalesPerson table (SalesPersonID int, SalesPersonName varchar(10))
DECLARE @Region table (RegionID int, RegionName varchar(15))
DECLARE @SalesPersonRegion table (SalesPersonID int, RegionID int)
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (1,'Jeff')
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (2,'Pat')
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (3,'Joe')
INSERT INTO @Region (RegionID, RegionName) VALUES (1,'North')
INSERT INTO @Region (RegionID, RegionName) VALUES (2,'South')
INSERT INTO @Region (RegionID, RegionName) VALUES (3,'East')
INSERT INTO @Region (RegionID, RegionName) VALUES (4,'West')
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,1)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,2)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,3)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,2)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,3)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,4)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (3,1)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (3,4)
一个简单的选择将让我得到每个销售人员,以及该销售人员所在的每个区域.
A simple select will get me each sales person, with each of that salesperson's region.
SELECT
sp.SalesPersonID,
sp.SalesPersonName,
r.RegionName
FROM @SalesPersonRegion spr
JOIN @SalesPerson sp
ON spr.SalesPersonID = sp.SalesPersonID
JOIN @Region r
ON spr.RegionID = r.RegionID
在这种情况下,它将返回 9 行.
In this case, it will return 9 Rows.
我想得到这样的结果:
SalesPersonID SalesPersonName Regions
1 Jeff North,South,East
2 Pat South,East,West
3 Joe North,West
SELECT
sp.SalesPersonID,
sp.SalesPersonName,
Regions = STUFF
(
(
SELECT ',' + r.RegionName
FROM @Region AS r
INNER JOIN @SalesPersonRegion AS spr
ON r.RegionID = spr.RegionID
WHERE spr.SalesPersonID = sp.SalesPersonID
ORDER BY r.RegionID
FOR XML PATH(''), TYPE
).value('.[1]','nvarchar(max)'),
1,1,''
)
FROM @SalesPerson AS sp
ORDER BY sp.SalesPersonID;
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