我有一组数据,需要为每个 CON/OWNER/METHOD/MATRIX 集提取一条记录.如果有一个非空的结果,我想要那个.否则,我想要 COUNT 最高的那个.我如何查询?
I have a set of data and need to pull out one record for each CON / OWNER / METHOD / MATRIX set. If there is a non-null RESULT, I want that one. Otherwise, I want the one with the highest COUNT. How do I query this?
CON OWNER METHOD MATRIX RESULT COUNT
*CON_1 OWNER_1 METHOD_A SOLID NULL 503
CON_1 OWNER_1 METHOD_A SOLID NULL 1
*CON_1 OWNER_1 METHOD_A SOIL NULL 1305
CON_1 OWNER_1 METHOD_A SOIL NULL 699
*CON_2 OWNER_2 METHOD_B SOLID 290 687
CON_2 OWNER_2 METHOD_B SOLID NULL NULL
CON_2 OWNER_2 METHOD_B SOLID 450 600
CON_2 OWNER_2 METHOD_B WATER NULL 1
*CON_2 OWNER_2 METHOD_B WATER 400 NULL
结果,我只想要加星标的记录,并且我正在展示每个集合是如何分组的.
for a result, I would like just the starred records, and I'm showing how each set is grouped.
这是糟糕的 SQL:
select top (1) CON, OWNER, METHOD, MATRIX, RESULT, COUNT
from #TempTable
group by CON, OWNER, METHOD, MATRIX
order by CON, OWNER, METHOD, MATRIX, COUNT
...因为我的计数不是聚合函数的一部分.它也不处理 RESULT 是否为 NULL,并且 top (1) 不会从每个分组返回 1.但是,我还没有通过使用更复杂的查询(例如基于 如何从子查询(在 SQL Server 中)中选择多个列,这些列应该为主中的每条记录有一个记录(选择前 1 个)查询?)
...because my count isn't part of the aggregate function. Nor does it deal with the RESULT being NULL or not, and top (1) won't return 1 from each grouping. However, I've not got farther by using a more complex query (such as based on the question at How can I select multiple columns from a subquery (in SQL Server) that should have one record (select top 1) for each record in the main query?)
如何从每个分组中选择一个?
How do I select one from each grouping?
试试这个,虽然不是 100% 确定语法正确,但很接近.
Try this, not 100% sure the syntax is right, but it is close.
select
*
from
(select
CON,
OWNER,
METHOD,
MATRIX,
RESULT,
COUNT,
RANK() OVER(PARTITION BY CON, OWNER, METHOD,MATRIX ORDER BY RESULT,COUNT DESC) as rnk
FROM #TempTable
) a
WHERE rnk = 1
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