带 for 循环的无符号 int 反向迭代

问题描述

我希望 for 循环中的迭代器变量作为 unsigned int 反向迭代到 0，我想不出与 i > 类似的比较.-1，就像如果它是 signed int 一样.

I want the iterator variable in a for loop to reverse iterate to 0 as an unsigned int, and I cannot think of a similar comparison to i > -1, as you would do if it was a signed int.

for (unsigned int i = 10; i <= 10; --i) { ... }

但这似乎很不清楚，因为它依赖于无符号整数的数值溢出超过 10.

But this seems very unclear, as it is relying on the numerical overflow of the unsigned integer to be above 10.

也许我只是没有清醒的头脑，但有什么更好的方法可以做到这一点...

Maybe I just don't have a clear head, but whats a better way to do this...

免责声明:这只是一个简单的用例，10 的上限是微不足道的，它可以是任何东西，并且 i 必须是一个 unsigned int.

for( unsigned int j = n; j-- > 0; ) { /*...*/ }