目前,我只能用这个做基于范围的循环:
Currently, I can only do ranged based loops with this:
for (auto& value : values)
但有时我需要一个值的迭代器,而不是引用(无论出于何种原因).有没有什么方法不需要遍历整个向量比较值?
But sometimes I need an iterator to the value, instead of a reference (For whatever reason). Is there any method without having to go through the whole vector comparing values?
使用旧的 for 循环:
for (auto it = values.begin(); it != values.end(); ++it )
{
auto & value = *it;
//...
}
有了这个,你就有了 value 和迭代器 it.想用什么就用什么.
With this, you've value as well as iterator it. Use whatever you want to use.
虽然我不推荐这样做,但是如果您想使用基于范围的 for 循环(是的,无论出于何种原因 :D),那么您可以这样做这个:
Although I wouldn't recommended this, but if you want to use range-based for loop (yeah, For whatever reason :D), then you can do this:
auto it = std::begin(values); //std::begin is a free function in C++11
for (auto& value : values)
{
//Use value or it - whatever you need!
//...
++it; //at the end OR make sure you do this in each iteration
}
这种方法避免了搜索给定的value,因为value 和it 总是同步的.
This approach avoids searching given value, since value and it are always in sync.
这篇关于使用基于范围的 for 循环时需要迭代器的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
编译器如何处理编译时分支?What do compilers do with compile-time branching?(编译器如何处理编译时分支?)
我可以使用 if (pointer) 而不是 if (pointer != NULL) 吗Can I use if (pointer) instead of if (pointer != NULL)?(我可以使用 if (pointer) 而不是 if (pointer != NULL) 吗?)
在 C/C++ 中检查空指针Checking for NULL pointer in C/C++(在 C/C++ 中检查空指针)
比较运算符的数学式链接-如“if((5<j<=1))&quMath-like chaining of the comparison operator - as in, quot;if ( (5lt;jlt;=1) )quot;(比较运算符的数学式链接-如“if((5<j<=1)))
“if constexpr()"之间的区别与“if()"Difference between quot;if constexpr()quot; Vs quot;if()quot;(“if constexpr()之间的区别与“if())
C++,'if' 表达式中的变量声明C++, variable declaration in #39;if#39; expression(C++,if 表达式中的变量声明)