在 C++ 中通过引用传递指针的原因?

问题描述

在什么情况下您希望在 C++ 中使用这种性质的代码?

Under which circumstances would you want to use code of this nature in c++?

void foo(type *&in) {...}

void fii() {
  type *choochoo;
  ...
  foo(choochoo);
}

推荐答案

如果您需要修改指针而不是指针指向的对象，您可能希望通过引用传递指针.

You would want to pass a pointer by reference if you have a need to modify the pointer rather than the object that the pointer is pointing to.

这类似于为什么使用双指针；使用对指针的引用比使用指针稍微安全一些.

This is similar to why double pointers are used; using a reference to a pointer is slightly safer than using pointers.

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