var a = (123.456).toString(36)//"3f.gez4w97ry0a18ymf6qadcxr"
现在,如何使用该字符串恢复为原始数字?
Now, how do I revert back to the original number using that string?
注意:parseInt(number,36) 仅适用于整数.
Note: parseInt(number,36) only works for integers.
您可以尝试使用 parseInt 分别解析整数和浮点部分,因为 parseFloat 不支持基数:
You could try parsing the integer and float parts separately with parseInt, as parseFloat does not support a radix:
function parseFloatInBase(n, radix) {
var nums = n.split(".")
// get the part before the decimal point
var iPart = parseInt(nums[0], radix)
// get the part after the decimal point
var fPart = parseInt(nums[1], radix) / Math.pow(radix, nums[1].length)
return iPart + fPart
}
// this will log 123.456:
console.log(parseFloatInBase("3f.gez4w97ry0a18ymf6qadcxr", 36))
我除以 radix ^ numLength 因为我基本上是在 numLength 空格上移动小数点.你会像在数学课上那样做,因为你知道除以 10 会将小数移动一个空格,因为大多数数学都是以 10 为底的.示例:
I am dividing by radix ^ numLength because I am basically moving the decimal point over numLength spaces. You would do this just like in math class, because as you know dividing by 10 moves the decimal over one space, because most math is in base 10. Example:
123456 / 10 / 10 / 10 = 123.456
这相当于
123456 / (10 * 10 * 10) = 123.456
因此
123456 / (10 ^ 3) = 123.456
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