首先我想说的是,我真的不知道如何解释我做了什么才能得到标题中提到的错误(uncaught TypeError: Illegal constructor
).我正在使用 gulpfile 将我的 Ecmascript 6 编译为纯 Javascript.我的 gulpfile 看起来像这样:
First of all I would like that say that I don't really know how I can explain what I did on order to get the error mentioned in the title (uncaught TypeError: Illegal constructor
). I am using gulpfile in order to compile my Ecmascript 6 to plain Javascript. My gulpfile looks like this:
var gulp = require('gulp');
var concat = require('gulp-concat');
var babel = require('gulp-babel');
gulp.task('compile', function () {
return gulp.src(['resources/assets/js/*.js', 'resources/assets/js/components/*.js'])
.pipe(babel({
presets: ['es2015']
}).on('error', logError))
.pipe(concat('bundle.js'))
.pipe(gulp.dest('public/js'));
});
gulp.task('watch', function () {
gulp.watch('resources/assets/js/**/*', ['compile']);
})
gulp.task('default', ['watch']);
function logError(err) {
console.log(err);
}
我有一个文件系统,在使用 Babel 编译后,所有文件都连接到一个文件 (bundle.js).
I have a filesystem where all files are concatenated to one file (bundle.js), after being compiled with Babel.
在浏览器控制台(Chrome 或 Firefox)中,错误出现并且位于下一行:
In the browsers console (either Chrome or Firefox), the error appears and it is located in the next line:
var _this = _possibleConstructorReturn(this, (Dropdown.__proto__ || Object.getPrototypeOf(Dropdown)).call(this, element));
这是未编译的代码:
class Dropdown extends Node {
constructor(element) {
super(element);
this.registerEvents(['click', 'change', 'blur']);
}
onClick() {
this.$element.addClass('clicked');
}
}
这是同一类的编译代码:
And this is the compiled code of the same class:
var Dropdown = function (_Node) {
_inherits(Dropdown, _Node);
function Dropdown(element) {
_classCallCheck(this, Dropdown);
var _this = _possibleConstructorReturn(this, (Dropdown.__proto__ || Object.getPrototypeOf(Dropdown)).call(this, element));
_this.registerEvents(['click', 'change', 'blur']);
return _this;
}
_createClass(Dropdown, [{
key: 'onClick',
value: function onClick() {
this.$element.addClass('clicked');
}
}]);
return Dropdown;
}(Node);
我没有使用 export default Dropdown
因为我没有在其他模块中导入模块(这不是必需的,因为每个文件都转换为一个文件,所有内容都可以访问).
I am not using export default Dropdown
because I am not importing modules in other modules (this is not needed because every file is converted to one file, where everything is accessible).
我做了一些研究,人们得到这个错误的唯一原因是因为有一个大写字母是不允许的.我没有找到有关此错误原因的任何其他信息.有人知道我为什么会收到此错误吗?有人有解决方案吗?
I did some research and the only reason why peoeple got this error was because there was a capital letter where none was allowed. I didn't find anything else about the cause of this error. Does someone have an idea why I get this error? And does someone have a solution?
看起来你正在尝试扩展 DOM 的 节点
.你不能这样做,它被定义为一个抽象接口,并且在浏览器中公开的主机提供的函数不能作为构造函数调用(即使是子类).
It looks like you're trying to extend DOM's Node
. You can't do that, it's defined as an abstract interface, and the host-provided function exposed in browsers for it can't be called as a constructor (even by subclasses).
这篇关于EcmaScript 6 的非法构造函数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!