期望不要抛出带参数的函数 - Jasmine

问题描述

我有获得 3 个参数的函数.我想检查这个函数没有抛出错误.我做了这样的事情:

I have function that gets 3 arguments. I want to check that this function not throwing an error. I did something like this:

expect(myFunc).not.toThrow();

问题是 myFunc 需要获取参数.如何发送参数?

The problem is myFunc need to get arguments. How can I send the arguments?

P.S 我试图传递它的参数，但我得到错误 myFunc(arg1, arg2, arg3) 不是一个函数.

P.S I tried to pass it argument but I got error that myFunc(arg1, arg2, arg3) is not a function.

推荐答案

toThrow 匹配器需要将函数作为参数传递给 expect，这样你就可以简单地包装你的函数调用在匿名函数中:

toThrow matcher requires function to be passed as argument to expect so you can simply wrap your function call in anonymous function:

expect(function() {
    myFunc(arg1, arg2, arg3);
}).not.toThrow();

您也可以使用 绑定创建函数的新版本"，在调用时将传递提供的参数:

You can also use bind to create new 'version' of your function that when called will be passed provided arguments:

expect(myFunc.bind(null, arg1, arg2, arg3)).not.toThrow();

这篇关于期望不要抛出带参数的函数 - Jasmine的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持html5模板网！