有没有办法用 Jasmine 验证间谍执行的顺序?

时间:2023-04-30
本文介绍了有没有办法用 Jasmine 验证间谍执行的顺序?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

限时送ChatGPT账号..

我有两个对象被 Jasmine 设置为间谍:

I've got two objects that have been set up as spies with Jasmine:

spyOn(obj, 'spy1');
spyOn(obj, 'spy2');

我需要验证对 spy1 的调用是否在对 spy2 的调用之前.我可以检查它们是否都被调用:

I need to verify that calls to spy1 come before calls to spy2. I can check if both of them are called:

expect(obj.spy1).toHaveBeenCalled();
expect(obj.spy2).toHaveBeenCalled();

但即使首先调用 obj.spy2() 也会通过.有没有一种简单的方法可以验证一个在另一个之前被调用?

but this will pass even if obj.spy2() was called first. Is there an easy way of verifying that one was called before the other?

推荐答案

貌似 Jasmine 的人看到这个帖子或者其他人喜欢,因为 这个功能存在.我不确定它已经存在了多久——他们所有回到 2.6 的 API 文档都提到了它,尽管他们存档的旧式文档都没有提到它.

Looks like the Jasmine folks saw this post or others like it, because this functionality exists. I'm not sure how long it's been around -- all of their API docs back to 2.6 mention it, though none of their archived older style docs mention it.

toHaveBeenCalledBefore(预期)
expect 实际值(a Spy) 在另一个 间谍.

toHaveBeenCalledBefore(expected)
expect the actual value (a Spy) to have been called before another Spy.

参数:

Name        Type    Description
expected    Spy     Spy that should have been called after the actual Spy.

您的示例失败看起来像 Expected spy spy1 to have been called before spy spy2.

A failure for your example looks like Expected spy spy1 to have been called before spy spy2.

这篇关于有没有办法用 Jasmine 验证间谍执行的顺序?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!

上一篇:Babel 将其替换为 undefined 下一篇:如何在 JavaScript 中模拟宏?

相关文章

最新文章