d3 v4 带 x 和 y 轴的拖动折线图

时间：2023-04-29

本文介绍了d3 v4 带 x 和 y 轴的拖动折线图的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

限时送ChatGPT账号..

我是 d3.js 的新手.我想用它的点来拖动一个折线图.没有 x 和 y 轴它工作正常.我已将此示例用作参考:https://bl.ocks.org/mbostock/4342190

I'm new to d3.js. I wanted to drag a line chart using its points. It is working fine without the x and y axes. I have used this example as reference: https://bl.ocks.org/mbostock/4342190

对于折线图的轴，该线未正确绘制.请查看下面的代码段.

With the axes to the line chart the line is not plotting correcly. Please have a look into the snippet below.

提前致谢.

<!DOCTYPE html>
<svg width="500" height="350"></svg>
<script src="https://d3js.org/d3.v4.min.js"></script>
<script>

var svg = d3.select("svg"),
    margin = {top: 20, right: 20, bottom: 30, left: 50},
    width = +svg.attr("width") - margin.left - margin.right,
    height = +svg.attr("height") - margin.top - margin.bottom;
    

let points = d3.range(1, 10).map(function(i) {
    return [i * width / 10, 50 + Math.random() * (height - 100)];
});
var x = d3.scaleLinear()
    .rangeRound([0, width]);

var y = d3.scaleLinear()
    .rangeRound([height, 0]);

var xAxis = d3.axisBottom(x),
    yAxis = d3.axisLeft(y);

var line = d3.line()
    .x(function(d) { return x(d[0]); })
    .y(function(d) { return y(d[1]); });
    
let drag = d3.drag()
        .on('start', dragstarted)
        .on('drag', dragged)
        .on('end', dragended);
        
svg.append('rect')
    .attr('class', 'zoom')
    .attr('cursor', 'move')
    .attr('fill', 'none')
    .attr('pointer-events', 'all')
    .attr('width', width)
    .attr('height', height)
    .attr('transform', 'translate(' + margin.left + ',' + margin.top + ')')

 var focus = svg.append("g")
                .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

x.domain(d3.extent(points, function(d) { return d[0]; }));
y.domain(d3.extent(points, function(d) { return d[1]; }));

focus.append("path")
    .datum(points)
    .attr("fill", "none")
    .attr("stroke", "steelblue")
    .attr("stroke-linejoin", "round")
    .attr("stroke-linecap", "round")
    .attr("stroke-width", 1.5)
    .attr("d", line);

focus.selectAll('circle')
    .data(points)
    .enter()
    .append('circle')
    .attr('r', 5.0)
    .attr('cx', function(d) { return x(d[0]);  })
    .attr('cy', function(d) { return y(d[1]); })
    .style('cursor', 'pointer')
    .style('fill', 'steelblue');

focus.selectAll('circle')
        .call(drag);

focus.append('g')
    .attr('class', 'axis axis--x')
    .attr('transform', 'translate(0,' + height + ')')
    .call(xAxis);
    
focus.append('g')
    .attr('class', 'axis axis--y')
    .call(yAxis);

function dragstarted(d) {
    d3.select(this).raise().classed('active', true);
}

function dragged(d) {
    d3.select(this)
        .attr('cx', d[0] = d3.event.x)
        .attr('cy', d[1] = d3.event.y)
    focus.select('path').attr('d', line);
}

function dragended(d) {
    d3.select(this).classed('active', false);
}

</script>

推荐答案

d3.event 保存像素位置，但您的绘图是由用户空间坐标驱动的.因此，您需要将这些像素位置转换为用户空间.您可以使用您的秤 invert 方法来做到这一点.

d3.event is holding pixel positions, but your plot is driven by user-space coordinates. So, you need to convert those pixel positions to user-space. You can use your scales invert method to do so.

function dragged(d) {
    d[0] = x.invert(d3.event.x); // convert to user-space
    d[1] = y.invert(d3.event.y);
    d3.select(this)
        .attr('cx', x(d[0])) // back to pixels
        .attr('cy', y(d[1]))
    focus.select('path').attr('d', line); //line does pixel conversion too
}

运行代码:

<!DOCTYPE html>
<svg width="500" height="350"></svg>
<script src="https://d3js.org/d3.v4.min.js"></script>
<script>

var svg = d3.select("svg"),
    margin = {top: 20, right: 20, bottom: 30, left: 50},
    width = +svg.attr("width") - margin.left - margin.right,
    height = +svg.attr("height") - margin.top - margin.bottom;
    

let points = d3.range(1, 10).map(function(i) {
    return [i * width / 10, 50 + Math.random() * (height - 100)];
});
var x = d3.scaleLinear()
    .rangeRound([0, width]);

var y = d3.scaleLinear()
    .rangeRound([height, 0]);

var xAxis = d3.axisBottom(x),
    yAxis = d3.axisLeft(y);

var line = d3.line()
    .x(function(d) { return x(d[0]); })
    .y(function(d) { return y(d[1]); });
    
let drag = d3.drag()
        .on('start', dragstarted)
        .on('drag', dragged)
        .on('end', dragended);
        
svg.append('rect')
    .attr('class', 'zoom')
    .attr('cursor', 'move')
    .attr('fill', 'none')
    .attr('pointer-events', 'all')
    .attr('width', width)
    .attr('height', height)
    .attr('transform', 'translate(' + margin.left + ',' + margin.top + ')')

 var focus = svg.append("g")
                .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

x.domain(d3.extent(points, function(d) { return d[0]; }));
y.domain(d3.extent(points, function(d) { return d[1]; }));

focus.append("path")
    .datum(points)
    .attr("fill", "none")
    .attr("stroke", "steelblue")
    .attr("stroke-linejoin", "round")
    .attr("stroke-linecap", "round")
    .attr("stroke-width", 1.5)
    .attr("d", line);

focus.selectAll('circle')
    .data(points)
    .enter()
    .append('circle')
    .attr('r', 5.0)
    .attr('cx', function(d) { return x(d[0]);  })
    .attr('cy', function(d) { return y(d[1]); })
    .style('cursor', 'pointer')
    .style('fill', 'steelblue');

focus.selectAll('circle')
        .call(drag);

focus.append('g')
    .attr('class', 'axis axis--x')
    .attr('transform', 'translate(0,' + height + ')')
    .call(xAxis);
    
focus.append('g')
    .attr('class', 'axis axis--y')
    .call(yAxis);

function dragstarted(d) {
    d3.select(this).raise().classed('active', true);
}

function dragged(d) {
    d[0] = x.invert(d3.event.x);
    d[1] = y.invert(d3.event.y);
    d3.select(this)
        .attr('cx', x(d[0]))
        .attr('cy', y(d[1]))
    focus.select('path').attr('d', line);
}

function dragended(d) {
    d3.select(this).classed('active', false);
}

</script>

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d3 v4 带 x 和 y 轴的拖动折线图

问题描述

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