如何将 YAML 文件解析/读取到 Python 对象中?
How to parse/read a YAML file into a Python object?
例如,这个 YAML:
For example, this YAML:
Person:
name: XYZ
到这个 Python 类:
To this Python class:
class Person(yaml.YAMLObject):
yaml_tag = 'Person'
def __init__(self, name):
self.name = name
顺便说一句,我正在使用 PyYAML.
I am using PyYAML by the way.
如果你的 YAML 文件如下所示:
If your YAML file looks like this:
# tree format
treeroot:
branch1:
name: Node 1
branch1-1:
name: Node 1-1
branch2:
name: Node 2
branch2-1:
name: Node 2-1
你已经像这样安装了 PyYAML
:
And you've installed PyYAML
like this:
pip install PyYAML
Python 代码如下所示:
And the Python code looks like this:
import yaml
with open('tree.yaml') as f:
# use safe_load instead load
dataMap = yaml.safe_load(f)
变量 dataMap
现在包含一个带有树数据的字典.如果你使用 PrettyPrint 打印 dataMap
,你会得到类似的东西:
The variable dataMap
now contains a dictionary with the tree data. If you print dataMap
using PrettyPrint, you will get something like:
{
'treeroot': {
'branch1': {
'branch1-1': {
'name': 'Node 1-1'
},
'name': 'Node 1'
},
'branch2': {
'branch2-1': {
'name': 'Node 2-1'
},
'name': 'Node 2'
}
}
}
所以,现在我们已经了解了如何将数据导入 Python 程序.保存数据同样简单:
So, now we have seen how to get data into our Python program. Saving data is just as easy:
with open('newtree.yaml', "w") as f:
yaml.dump(dataMap, f)
你有一本字典,现在你必须把它转换成一个 Python 对象:
You have a dictionary, and now you have to convert it to a Python object:
class Struct:
def __init__(self, **entries):
self.__dict__.update(entries)
那么你可以使用:
>>> args = your YAML dictionary
>>> s = Struct(**args)
>>> s
<__main__.Struct instance at 0x01D6A738>
>>> s...
并遵循将 Python dict 转换为对象".
有关更多信息,您可以查看 pyyaml.org 和 这个.
For more information you can look at pyyaml.org and this.
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