我有一个只保存用户 ID 的机器人(这样工作会更好).现在我想从那个 id 中获取用户对象.
I have a bot which only saves the id of a user (it's better working like that). Now I want to get the user-object from that id.
我尝试了以下对我不起作用的方法,也许我做错了什么..
I tried following which doesn't work for me, maybe I have made something wrong..
client = discord.Client
client.get_user(id)
和client.get_user_info(id)
代码如下:
import discord
class MyClient(discord.Client):
ntd = name_table.get_all_records() #google sheets api: returns a list of dicts
async def on_message(self, message):
print(message.content[1])
if message.author == client.user:
return
if isinstance(message.channel, discord.channel.DMChannel):
await self.handle_DM(message)
if message.content[0] == "/":
if message.content.split(" ")[0].lower() == "/rank":
await self.rank_command(message)
async def rank_command(self, message):
if len(message.content.split(" ")) < 2:
await message.channel.send(
message.author.mention + "/rank takes 2 or 3 arguments. Do '/rank ?' for help.")
try:
if message.content.split(" ")[1] == "?":
await self.help("rank", message)
return
except:
pass
try:
if message.content.split(" ")[1] == "top":
await self.top_rank_command(message)
return
except:
pass
async def top_rank_command(message):
print("Top rank entered")
_user = await client.fetch_user(372746847393021953) #my id: Cluebo#2312
print(_user)
print("Top rank end")
执行这个,它只会打印Top rank enter",而不是user或Top rank end"但是,我没有收到错误消息.该方法就停在那里(机器人在 Heroku 上运行).提前致谢!
Executing this, it will only print "Top rank entered" but not the user or "Top rank end"
However, I did not get an error message. The method just stops there (The bot is running on Heroku).
Thanks in advance!
从一个id获取用户有两种方法:
There are two methods to get a user from an id:
Client.fetch_user(id)(或 Bot.fetch_user(id)) → 返回一个 discord.User 对象Guild.fetch_member(id) → 返回一个 discord.Member 对象以下是一些示例(同时使用 Client 和 Bot):
Here are some examples (using both Client and Bot):
#Get a discord.User object
@client.event
async def on_message(message):
content = message.content[6:]
if message.content.startswith('!find'):
user = await client.fetch_user(int(content))
print(user)
else:
pass
@bot.command()
async def find(ctx, id: int):
user = await bot.fetch_user(id)
print(user)
#Get a discord.Member object
@client.event
async def on_message(message):
content = message.content[6:]
if message.content.startswith('!find'):
member = await message.guild.fetch_member(int(content))
print(member)
else:
pass
@bot.command()
async def find(ctx, id: int):
member = await ctx.guild.fetch_member(id)
print(member)
使用这些示例,您只需在 discord 中编写 !find [id] ,它就会打印它在终端中获取的对象
With those examples, you'd just have to write !find [id] in discord and it would print the object it fetched in your terminal
这篇关于Discord.py:获取带有 id 的用户对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
python:不同包下同名的两个模块和类python: Two modules and classes with the same name under different packages(python:不同包下同名的两个模块和类)
配置 Python 以使用站点包的其他位置Configuring Python to use additional locations for site-packages(配置 Python 以使用站点包的其他位置)
如何在不重复导入顶级名称的情况下构造python包How to structure python packages without repeating top level name for import(如何在不重复导入顶级名称的情况下构造python包)
在 OpenShift 上安装 python 包Install python packages on OpenShift(在 OpenShift 上安装 python 包)
如何刷新 sys.path?How to refresh sys.path?(如何刷新 sys.path?)
分发带有已编译动态共享库的 Python 包Distribute a Python package with a compiled dynamic shared library(分发带有已编译动态共享库的 Python 包)