我想要一个长时间运行的进程通过队列(或类似的东西)返回它的进度,我将把它提供给进度条对话框.当过程完成时,我还需要结果.此处的测试示例失败并出现 RuntimeError: Queue objects should only be shared between processes through inheritance
.
I want a long-running process to return its progress over a Queue (or something similar) which I will feed to a progress bar dialog. I also need the result when the process is completed. A test example here fails with a RuntimeError: Queue objects should only be shared between processes through inheritance
.
import multiprocessing, time
def task(args):
count = args[0]
queue = args[1]
for i in xrange(count):
queue.put("%d mississippi" % i)
return "Done"
def main():
q = multiprocessing.Queue()
pool = multiprocessing.Pool()
result = pool.map_async(task, [(x, q) for x in range(10)])
time.sleep(1)
while not q.empty():
print q.get()
print result.get()
if __name__ == "__main__":
main()
我已经能够使用单独的 Process 对象(我 am 允许传递 Queue 引用)使其工作,但是我没有一个池来管理我的许多进程想启动.有什么更好的模式建议吗?
I've been able to get this to work using individual Process objects (where I am alowed to pass a Queue reference) but then I don't have a pool to manage the many processes I want to launch. Any advise on a better pattern for this?
以下代码似乎可以工作:
The following code seems to work:
import multiprocessing, time
def task(args):
count = args[0]
queue = args[1]
for i in xrange(count):
queue.put("%d mississippi" % i)
return "Done"
def main():
manager = multiprocessing.Manager()
q = manager.Queue()
pool = multiprocessing.Pool()
result = pool.map_async(task, [(x, q) for x in range(10)])
time.sleep(1)
while not q.empty():
print q.get()
print result.get()
if __name__ == "__main__":
main()
请注意,队列来自 manager.Queue() 而不是 multiprocessing.Queue().感谢 Alex 为我指明了这个方向.
Note that the Queue is got from a manager.Queue() rather than multiprocessing.Queue(). Thanks Alex for pointing me in this direction.
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