在 PyQt5 中嵌入终端

问题描述

所以我一直在尝试创建自己的终端，但事实证明这非常有问题，而且看起来不专业.

So I've been trying to create my own terminal but that has been proven very glitchy and not professional looking.

然后我偶然发现了这段用于 PyQt4 的代码:

Then I stumbled across this code which is for PyQt4:

#!/usr/bin/env python
#-*- coding:utf-8 -*-

import sys
from PyQt4.QtCore import *
from PyQt4.QtGui import *


class embterminal(QWidget):

    def __init__(self):
        QWidget.__init__(self)
        self.process = QProcess(self)
        self.terminal = QWidget(self)
        layout = QVBoxLayout(self)
        layout.addWidget(self.terminal)
        #self.process.start(
                #'xterm',['-into', str(self.terminal.winId())])
        # Works also with urxvt:
        self.process.start(
                'urxvt',['-embed', str(self.terminal.winId())])


if __name__ == "__main__":
    app = QApplication(sys.argv)
    main = embterminal()
    main.show()
    sys.exit(app.exec_())

由于我的应用程序是用 PyQt5 编写的，我自然而然地尝试将该代码移植到 PyQt5.我从 PyQt4.QtCore import * 更改了 从 PyQt4.QtGui 导入 * 到 从 PyQt5.QtCore 导入 *from PyQt5.QtGui import * 并添加 from PyQt5.QtWidgets import *

Since my application is written in PyQt5, I naturally tried porting that code to PyQt5. I changed from PyQt4.QtCore import * from PyQt4.QtGui import * to from PyQt5.QtCore import * from PyQt5.QtGui import * and added from PyQt5.QtWidgets import *

然后当我运行我的代码时，我意识到终端没有弹出.

Then when I ran my code I realized the terminal didn't pop up.

我想知道为什么会发生这种情况，是否有解决方法?

I wonder why does this happen and is there a workaround ?

我也想知道我是否可以在同一个项目/文件中同时使用 PyQt5 和 PyQt4.

I also wonder if I can use both PyQt5 and PyQt4 in the same project/file, even.

推荐答案

在 PyQt.QWidget.winId() 返回一个 sip.voidptr 对象，但如果将其转换为整数，它应该可以工作.这是一个工作示例:

In PyQt. QWidget.winId() returns a sip.voidptr object, but if you convert it to an integer, it should work. Here's a working example:

import sys
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *

class Window(QWidget):
    def __init__(self):
        super().__init__()
        self.process = QProcess(self)
        self.terminal = QWidget(self)
        layout = QVBoxLayout(self)
        layout.addWidget(self.terminal)
        wid = str(int(self.terminal.winId()))
        self.process.start('urxvt', ['-embed', wid])

    def closeEvent(self, event):
        self.process.terminate()
        self.process.waitForFinished(1000)

if __name__ == "__main__":

    app = QApplication(sys.argv)
    window = Window()
    window.setGeometry(100, 100, 800, 600)
    window.show()
    sys.exit(app.exec_())

这篇关于在 PyQt5 中嵌入终端的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持html5模板网！