我尝试使用 mock
在 python 中编写一些单元测试.
I try to use mock
to write some unit-tests in python.
例如我有以下课程:
class TCPHandler(socketserver.BaseRequestHandler):
def handle(self):
self.data = self.request.recv(1024).strip()
我只想测试 handle
方法.无需对 socketserver.BaseRequestHandler
做任何假设.例如,我想断言 handle
使用参数 1024
调用 recv
.可以用模拟做这样的事情吗?IE.用模拟替换基类 socketserver.BaseRequestHandler
?还是我偏离了这个想法?
And I only want to test the handle
method. Without having to assume anything about socketserver.BaseRequestHandler
. I for example want to assert that handle
calls recv
with the argument 1024
. Is it possible to do such thing with mock? I.e. replacing the base class socketserver.BaseRequestHandler
with a mock? Or am I off track with that idea?
在 ecatmur 的回答下(谢谢!)我首先尝试了以下方法:
With the answer of ecatmur (thank you!) I first tried the following:
patcher = patch.object(TCPHandler, '__bases__', (Mock,))
with patcher:
patcher.is_local = True
handler = TCPHandler()
handler.handle()
但是现在 handle
不再被调用并且 dir(handler)
给出:
But now handle
is not called anylonger and dir(handler)
gives:
['assert_any_call', 'assert_called_once_with', 'assert_called_with', 'assert_has_calls', 'attach_mock', 'call_args', 'call_args_list', 'call_count', 'called', 'configure_mock', 'method_calls', 'mock_add_spec', 'mock_calls', 'reset_mock', 'return_value', 'side_effect']
type(handler)
给出<class 'mock.TCPHandler'>
我解释说,修补基类也会将我的派生类变成一个模拟类.
Which I interpret that patching the base class also turns my derived class into a mock.
我现在尝试了另一个想法:
I now gave another idea a try:
mock = MagicMock()
TCPHandler.handle(mock)
#assertions
但是模拟似乎没有被调用.
However the mock seems not to be called.
您可以通过修补派生类的 __bases__
来做到这一点:
You can do this by patching the derived class's __bases__
:
def test_derived():
patcher = mock.patch.object(Derived, '__bases__', (mock.Mock,))
with patcher:
patcher.is_local = True
d = Derived()
print d.foo()
is_local
hack 是阻止 mock.patch
在反转补丁时尝试调用 delattr
所必需的.
The is_local
hack is necessary to stop mock.patch
from trying to call delattr
when reversing the patch.
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