使用 Laravel 5.4 和 Passport 进行多重身份验证

问题描述

我正在尝试使用 Laravel Passport 设置多重身份验证，但它似乎不支持它.我正在使用密码授予来颁发令牌，这要求我传递想要访问令牌的用户的用户名/密码.

I am trying to setup multi auth with Laravel Passport, but it doesn't seem to support it. I am using the Password Grant to issue tokens which requires me to pass username/password of the user wanting access tokens.

我设置了 3 个身份验证防护/提供程序，总共 4 个.用户、供应商、管理员和 API

I have 3 auth guards/providers setup, 4 in total. Users, Vendors, Admins and API

其中 2 个 Auth 需要通行证访问权限，因此每个用户都需要能够颁发令牌.但是 Passport 会自动采用 API 身份验证提供程序，但我希望根据登录的用户进行更改..

2 of the Auths need passport access, so each user needs to be able to issue tokens. But Passport automatically takes the API auth provider, but I want this to change based on which user is logging in.. If user does then the User provider and if its a vendor then the Vendor provider.

但是 Passport 目前只支持 1 种用户类型，所以默认为 API 提供者.

But the way Passport currently only supports only 1 user type, so its defaulting to the API provider.

有什么更好的方法吗?或者我应该改用基于角色的身份验证.

Is there something better for this? or should I go with roles based authentication instead.

推荐答案

如果您仍然需要.

我更喜欢使用角色，有一个很棒的插件:https://github.com/larapacks/授权

I prefer go with roles, there is an amazing plugin for that: https://github.com/larapacks/authorization

但如果您有某种需要，您可以按照以下步骤使用.

But if you somehow needs that, you will be able to use following the steps bellow.

对于多个守卫，您将不得不覆盖一些代码.

For multi guards, you will have to overwrite some code.

您不是加载 PassportServiceProvider，而是创建自己的并扩展 PassportServiceProvider 并覆盖方法 makePasswordGrant.在此方法中，您将为自己的扩展存储库更改 Passport UserRepository.在用户存储库上，您必须将静态模型配置更改为动态模型配置(我从请求属性加载，但您可以从任何地方获取).

Instead of loading PassportServiceProvider, you create your own and extends the PassportServiceProvider and overwrites the method makePasswordGrant. On this method, you will change the Passport UserRepository for your own repository extended. On user repository you must to change the static model config for a dynamic one (I load from request attributes, but you can get from anywhere).

您可能需要覆盖其他内容，但我进行了测试并有效.

You may have to overwrite something else, but I made a test and works.

例如:

PassportServiceProvider

PassportServiceProvider

namespace AppProviders;

use LeagueOAuth2ServerAuthorizationServer;
use LeagueOAuth2ServerGrantPasswordGrant;
use LaravelPassportPassportServiceProvider as BasePassportServiceProvider;
use LaravelPassportPassport;

class PassportServiceProvider extends BasePassportServiceProvider
{
    /**
     * Create and configure a Password grant instance.
     *
     * @return PasswordGrant
     */
    protected function makePasswordGrant()
    {
        $grant = new PasswordGrant(
            $this->app->make(AppRepositoriesPassportUserRepository::class),
            $this->app->make(LaravelPassportBridgeRefreshTokenRepository::class)
        );

        $grant->setRefreshTokenTTL(Passport::refreshTokensExpireIn());

        return $grant;
    }

}

用户存储库

namespace AppRepositories;

use App;
use IlluminateHttpRequest;
use LeagueOAuth2ServerEntitiesClientEntityInterface;
use LaravelPassportBridgeUserRepository;
use LaravelPassportBridgeUser;
use RuntimeException;

class PassportUserRepository extends UserRepository
{
    /**
     * {@inheritdoc}
     */
    public function getUserEntityByUserCredentials($username, $password, $grantType, ClientEntityInterface $clientEntity)
    {
        $guard = App::make(Request::class)->attributes->get('guard') ?: 'api';
        $provider = config("auth.guards.{$guard}.provider");


        if (is_null($model = config("auth.providers.{$provider}.model"))) {
            throw new RuntimeException('Unable to determine user model from configuration.');
        }


        if (method_exists($model, 'findForPassport')) {
            $user = (new $model)->findForPassport($username);
        } else {
            $user = (new $model)->where('email', $username)->first();
        }


        if (! $user ) {
            return;
        } elseif (method_exists($user, 'validateForPassportPasswordGrant')) {
            if (! $user->validateForPassportPasswordGrant($password)) {
                return;
            }
        } elseif (! $this->hasher->check($password, $user->password)) {
            return;
        }

        return new User($user->getAuthIdentifier());
    }
}

PS:对不起，我的英语不好.

PS: Sorry my bad english.

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