如何关闭 PHP 通知?
时间：2023-09-21问题描述
Notice: Constant DIR_FS_CATALOG already defined
我已经在 php.ini<中注释掉了 display_errors/code>，但不起作用.
I've already commented out display_errors in php.ini, but is not working.
如何让 PHP 不向浏览器输出这些东西?
How do I make PHP to not output such things to browsers?
更新
我把 display_errors = Off 放在那里，但它仍然报告这样的通知，
I put display_errors = Off there but it's still reporting such notices,
这是 PHP 5.3 的问题吗?
Is this an issue with PHP 5.3?
也报告大量调用堆栈..
推荐答案
您可以将 display_errors 设置为 0 或使用 error_reporting() 函数.
You can set display_errors to 0 or use the error_reporting() function.
然而，通知很烦人(我可以部分同情)但他们服务于一个目的.你不应该定义一个常量两次，第二次将不起作用，常量将保持不变！
However, notices are annoying (I can partly sympathize) but they serve a purpose. You shouldn't be defining a constant twice, the second time won't work and the constant will remain unchanged!
这篇关于如何关闭 PHP 通知?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持html5模板网！
相关文章
MySQLi准备好的语句&foreach 循环MySQLi prepared statement amp; foreach loop(MySQLi准备好的语句amp;foreach 循环)- mysqli_insert_id() 是从整个服务器还是从同一用户获Is mysqli_insert_id() gets record from whole server or from same user?(mysqli_insert_id() 是从整个服务器还是从同一用户获取记录?)
- PHP MySQLi 无法识别登录信息PHP MySQLi doesn#39;t recognize login info(PHP MySQLi 无法识别登录信息)
- mysqli_select_db() 需要 2 个参数mysqli_select_db() expects exactly 2 parameters(mysqli_select_db() 需要 2 个参数)
- Php mysql pdo 查询:用查询结果填充变量Php mysql pdo query: fill up variable with query result(Php mysql pdo 查询:用查询结果填充变量)
- MySQLI 28000/1045 用户“root"@“localhost"的访问MySQLI 28000/1045 Access denied for user #39;root#39;@#39;localhost#39;(MySQLI 28000/1045 用户“root@“localhost的访问被拒绝)