我有以下几点:
$counter = 1;
while($row= mysql_fetch_assoc($result)) {
$counter2 = $counter++;
echo($counter2 . $row['foo']);
}
是否有更简单的方法可以为每个结果获得 1、2、3 等,或者这是最好的方法?
Is there an easier way to get 1,2,3 etc for each result or is this the best way?
谢谢
你不需要 $counter2.$counter++ 很好.如果您使用 preincrement 而不是 postincrement,您甚至可以在与 echo 相同的行上执行此操作.
You don't need $counter2. $counter++ is fine. You can even do it on the same line as the echo if you use preincrement instead of postincrement.
$counter = 0;
while($row= mysql_fetch_assoc($result)) {
echo(++$counter . $row['foo']);
}
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