我有一个 mysqli 查询,我需要将其格式化为移动应用程序的 JSON.
我已经设法为查询结果生成了一个 XML 文档,但是我正在寻找更轻量级的东西.(请参阅下面我当前的 XML 代码)
$mysql = new mysqli(DB_SERVER,DB_USER,DB_PASSWORD,DB_NAME) or die('连接数据库时出现问题');$stmt = $mysql->prepare('SELECT DISTINCT title FROM Section ORDER BY title ASC');$stmt->execute();$stmt->bind_result($title);//创建xml格式$doc = new DomDocument('1.0');//创建根节点$root = $doc->createElement('xml');$root = $doc->appendChild($root);//为每一行添加节点while($row = $stmt->fetch()) :$occ = $doc->createElement('data');$occ = $root->appendChild($occ);$child = $doc->createElement('section');$child = $occ->appendChild($child);$value = $doc->createTextNode($title);$value = $child->appendChild($value);终了;$xml_string = $doc->saveXML();header('Content-Type: application/xml; charset=ISO-8859-1');//输出 xml jQuery 就绪回声 $xml_string;$mysqli = new mysqli('localhost','user','password','myDatabaseName');$myArray = array();if ($result = $mysqli->query("SELECT * FROM phase1")) {while($row = $result->fetch_array(MYSQLI_ASSOC)) {$myArray[] = $row;}回声 json_encode($myArray);}$result->close();$mysqli->close();$row = $result->fetch_array(MYSQLI_ASSOC)$myArray[] = $row输出如下:
<预><代码>[{"id":"31","name":"pruduct_name1","price":"98"},{"id":"30","name":"pruduct_name2","price":"23"}]如果你想要另一种风格,你可以试试这个:
$row = $result->fetch_row()$myArray[] = $row输出如下:
<预><代码>[["31","pruduct_name1","98"],["30","pruduct_name2","23"]]I have a mysqli query which I need to format as JSON for a mobile application.
I have managed to produce an XML document for the query results, however I am looking for something more lightweight. (See below for my current XML code)
$mysql = new mysqli(DB_SERVER,DB_USER,DB_PASSWORD,DB_NAME) or die('There was a problem connecting to the database');
$stmt = $mysql->prepare('SELECT DISTINCT title FROM sections ORDER BY title ASC');
$stmt->execute();
$stmt->bind_result($title);
// create xml format
$doc = new DomDocument('1.0');
// create root node
$root = $doc->createElement('xml');
$root = $doc->appendChild($root);
// add node for each row
while($row = $stmt->fetch()) :
$occ = $doc->createElement('data');
$occ = $root->appendChild($occ);
$child = $doc->createElement('section');
$child = $occ->appendChild($child);
$value = $doc->createTextNode($title);
$value = $child->appendChild($value);
endwhile;
$xml_string = $doc->saveXML();
header('Content-Type: application/xml; charset=ISO-8859-1');
// output xml jQuery ready
echo $xml_string;
$mysqli = new mysqli('localhost','user','password','myDatabaseName');
$myArray = array();
if ($result = $mysqli->query("SELECT * FROM phase1")) {
while($row = $result->fetch_array(MYSQLI_ASSOC)) {
$myArray[] = $row;
}
echo json_encode($myArray);
}
$result->close();
$mysqli->close();
$row = $result->fetch_array(MYSQLI_ASSOC)$myArray[] = $rowoutput like this:
[
{"id":"31","name":"pruduct_name1","price":"98"},
{"id":"30","name":"pruduct_name2","price":"23"}
]
If you want another style, you can try this:
$row = $result->fetch_row()$myArray[] = $rowoutput will like this:
[
["31","pruduct_name1","98"],
["30","pruduct_name2","23"]
]
这篇关于如何将 mysqli 结果转换为 JSON?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
mysql 中的 store_result() 和 get_result() 返回 falsestore_result() and get_result() in mysql returns false(mysql 中的 store_result() 和 get_result() 返回 false)
调用未定义的函数 mysqli_result::num_rows()Call to undefined function mysqli_result::num_rows()(调用未定义的函数 mysqli_result::num_rows())
PHP 准备好的语句问题PHP Prepared Statement Problems(PHP 准备好的语句问题)
mysqli_fetch_array 只返回一个结果mysqli_fetch_array returning only one result(mysqli_fetch_array 只返回一个结果)
PHP MySQLi 多次插入PHP MySQLi Multiple Inserts(PHP MySQLi 多次插入)
如何确保 MySQL 中的值在 PHP 中保持其类型?How do I make sure that values from MySQL keep their type in PHP?(如何确保 MySQL 中的值在 PHP 中保持其类型?)