我之前没有使用过 $_SERVER['HTTP_REFERER'],我不知道如何使用它来通过点击 Google 搜索结果中的链接来找到访问我网站的用户.用户可以来自 google.com、google.co.uk 等......
I haven't used $_SERVER['HTTP_REFERER'] before and i dont knw how i can use that to find that user came to my site by clicking on a link in Google search results. User can come from google.com, google.co.uk etc....
非常感谢帮助.
$url = $_SERVER['HTTP_REFERER'];
$query = parse_url ($url, PHP_URL_QUERY);
$host = parse_url ($url, PHP_URL_HOST);
if (strstr ($query, 'q=') && strstr ($host, 'google.')) {
// user came from google
else {
// user didnt come from google
}
这篇关于我如何使用 $_SERVER['HTTP_REFERER'] 来查找来自 google 的用户?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持html5模板网!
在 SELECT(MYSQL/PHP) 中加入 2 个表Joining 2 tables in SELECT(MYSQL/PHP)(在 SELECT(MYSQL/PHP) 中加入 2 个表)
如何使<option selected=“selected">由How to make lt;option selected=quot;selectedquot;gt; set by MySQL and PHP?(如何使lt;option selected=“selectedgt;由 MySQL 和 PHP 设置?)
使用 PHP 中的数组自动填充选择框Auto populate a select box using an array in PHP(使用 PHP 中的数组自动填充选择框)
PHP SQL SELECT where like search item with multiple wordsPHP SQL SELECT where like search item with multiple words(PHP SQL SELECT where like search item with multiple words)
json_encode 从 MSSQL-SELECT 产生 JSON_ERROR_UTF8json_encode produce JSON_ERROR_UTF8 from MSSQL-SELECT(json_encode 从 MSSQL-SELECT 产生 JSON_ERROR_UTF8)
MySQL ORDER BY rand(),名称 ASCMySQL ORDER BY rand(), name ASC(MySQL ORDER BY rand(),名称 ASC)