我在使用简单代码时不断收到标题中的错误:
I keep getting the error in the title, while using a simple code:
require_once('sdk/src/facebook.php');
require_once("AppInfo.php");
function idx(array $array, $key, $default = null) {
return array_key_exists($key, $array) ? $array[$key] : $default;
}
function he($str) {
return htmlentities($str, ENT_QUOTES, "UTF-8");
}
$facebook = new Facebook(array(
'appId' => AppInfo::appID(),
'secret' => AppInfo::appSecret(),
'sharedSession' => true,
'trustForwarded' => true,
));
$arrayForJSON=array();
$user = $facebook->getUser();
$friends = idx($facebook->api('/me/friends'), 'data', array());
if ($friends) {
$arrayForJSON['friends']=$friends;
}
print_r($friends);
我真的不知道如何解决它,我一直在stackoverflow上搜索并尝试了很多答案
I really don't know how to solve it, I've been searching and trying many answers on stackoverflow
如果没有重定向用户到登录链接,则需要检查是否已经登录
you need to check if already login if not redirect the user to login link
require '../src/facebook.php';
// Create our Application instance (replace this with your appId and secret).
$facebook = new Facebook(array(
'appId' => '191149314281714',
'secret' => '73b67bf1c825fa47efae70a46c18906b',
));
// Get User ID
$user = $facebook->getUser();
// We may or may not have this data based on whether the user is logged in.
//
// If we have a $user id here, it means we know the user is logged into
// Facebook, but we don't know if the access token is valid. An access
// token is invalid if the user logged out of Facebook.
if ($user) {
try {
// Proceed knowing you have a logged in user who's authenticated.
// $user_profile = $facebook->api('/me');
$friends = idx($facebook->api('/me/friends'), 'data', array());
} catch (FacebookApiException $e) {
error_log($e);
$user = null;
}
}
// Login or logout url will be needed depending on current user state.
if ($user) {
$logoutUrl = $facebook->getLogoutUrl();
} else {
$loginUrl = $facebook->getLoginUrl(array('scope'=>'offline_access'));
}
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