如何在 Storyboard 中的任何 ViewController 之外设计单

问题描述

我想设计一个 UIView，它比 Storyboard (iOS 5) 中的 ViewController 大.

I would like to design a UIView, which is larger than a ViewController in Storyboard (iOS 5).

UIView 应该用作 UIScrollView 的子视图，因此比我现有的任何 ViewController 都大.如何在 Storyboard 中创建这样的 UIView 并将其与我的 UIScrollView 关联?

The UIView should be used as the subview of a UIScrollView and hence be larger than any of my existing ViewControllers. How can I create such a UIView in Storyboard and associate it with my UIScrollView?

如果可能，我希望不使用 xib 文件.

I would like to do this without xib files if possible.

谢谢！

推荐答案

除了使用 xibs，我没有其他选择，但它并不那么烦人:

I see no other option than using xibs, but it's not that annoying:

//We have file called "View.xib" in our project. It contains one SINGLE view
NSArray *xibContents = [[NSBundle mainBundle] loadNibNamed:@"View" owner:self options:nil];
UIView *view = [xibContents lastObject]; //safer than objectAtIndex:0

[self.scrollview addSubview:view];
self.scrollview.contentSize = view.frame.size; 

为了建立 IB 连接，您可以将 xib 中的 filesOwner 类设置为您的 viewController，然后像往常一样连接.

In order to make IB connections you can set the filesOwner class in the xib to be your viewController, and connect like usual.

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