我有 2 种口味,比如说香草和巧克力.我也有 Debug 和 Release 构建类型,我需要 Vanilla Release 的字段为 true,而其他 3 个组合应该为 false.
I have 2 flavors, lets say Vanilla and Chocolate. I also have Debug and Release build types, and I need Vanilla Release to have a field true, while the other 3 combinations should be false.
def BOOLEAN = "boolean"
def VARIABLE = "VARIABLE"
def TRUE = "true"
def FALSE = "false"
VANILLA {
debug {
buildConfigField BOOLEAN, VARIABLE, FALSE
}
release {
buildConfigField BOOLEAN, VARIABLE, TRUE
}
}
CHOCOLATE {
buildConfigField BOOLEAN, VARIABLE, FALSE
}
我遇到了一个错误,所以我猜调试和发布技巧不起作用.可以这样做吗?
I'm having an error, so I guess the debug and release trick doesnt work. It is possible to do this?
循环变体并检查它们的名称:
Loop the variants and check their names:
productFlavors {
vanilla {}
chocolate {}
}
applicationVariants.all { variant ->
println("Iterating variant: " + variant.getName())
if (variant.getName() == "chocolateDebug") {
variant.buildConfigField "boolean", "VARIABLE", "true"
} else {
variant.buildConfigField "boolean", "VARIABLE", "false"
}
}
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