在我的实际项目中偶然发生的这里是我修改后的小程序.
In my actual project It happened accidentally here is my modified small program.
我不明白为什么它会输出 10?
I can't figure out why it is giving output 10?
public class Int
{
public static void main(String args[])
{
int j=012;//accidentaly i put zero
System.out.println(j);// prints 10??
}
}
在那之后,我放了两个零,仍然给出输出 10.
After that, I put two zeros still giving output 10.
然后我将 012 更改为 0123,现在输出 83?
Then I change 012 to 0123 and now it is giving output 83?
谁能解释一下原因?
比我把 012 改成 0123 现在输出 83 吗?
Than I change 012 to 0123 and now it is giving output 83?
因为,它被视为八进制基数 (8),因为该数字的前导是 0.所以,它对应的十进制值为10.
Because, it's taken as octal base (8), since that numeral have 0 in leading. So, it's corresponding decimal value is 10.
012:
(2 * 8 ^ 0) + (1 * 8 ^ 1) = 10
0123:
(3 * 8 ^ 0) + (2 * 8 ^ 1) + (1 * 8 ^ 2) = 83
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