下面的代码让我很困惑,因为它提供了两种不同的输出.代码在 jdk 1.7 上测试过.
The following code seemed really confusing to me since it provided two different outputs.The code was tested on jdk 1.7.
public class NotEq {
public static void main(String[] args) {
ver1();
System.out.println();
ver2();
}
public static void ver1() {
Integer a = 128;
Integer b = 128;
if (a == b) {
System.out.println("Equal Object");
}
if (a != b) {
System.out.println("Different objects");
}
if (a.equals(b)) {
System.out.println("Meaningfully equal.");
}
}
public static void ver2() {
Integer i1 = 127;
Integer i2 = 127;
if (i1 == i2) {
System.out.println("Equal Object");
}
if (i1 != i2){
System.out.println("Different objects");
}
if (i1.equals(i2)){
System.out.println("Meaningfully equal");
}
}
}
输出:
[ver1 输出]
不同的对象
有意义的平等.
[ver1 output]
Different objects
Meaningfully equal.
[ver2 输出]
相等对象
有意义的平等
[ver2 output]
Equal Object
Meaningfully equal
为什么 == 和 != 测试会为 ver1() 和 ver2() 生成不同的结果,而相同的数字远小于 Integer.MAX_VALUE?是否可以断定 == 检查大于 127 的数字(对于像代码中显示的 Integer 这样的包装类)完全是浪费时间?
Why the == and != testing produces different results for ver1() and ver2() for same number much less than the Integer.MAX_VALUE? Can it be concluded that == checking for numbers greater than 127 (for wrapper classes like Integer as shown in the code) is totally waste of time?
为 -128 和 127 之间的值缓存整数,因此 Integer i = 127
将始终返回相同的引用.Integer j = 128
不一定会这样做.然后,您将需要使用 equals
来测试底层 int
的相等性.
Integers are cached for values between -128 and 127 so Integer i = 127
will always return the same reference. Integer j = 128
will not necessarily do so. You will then need to use equals
to test for equality of the underlying int
.
这是 Java 语言规范:
如果被装箱的值 p 是真、假、一个字节或 u0000 到 u007f 范围内的一个字符,或者一个介于 -128 和 127(包括)之间的 int 或短数字,则令 r1 和 r2 为p 的任意两次装箱转换的结果.r1 == r2 总是如此.
If the value p being boxed is true, false, a byte, or a char in the range u0000 to u007f, or an int or short number between -128 and 127 (inclusive), then let r1 and r2 be the results of any two boxing conversions of p. It is always the case that r1 == r2.
但是对 Integer j = 128
的 2 次调用可能会返回相同的引用(不保证):
But 2 calls to Integer j = 128
might return the same reference (not guaranteed):
例如,内存限制较少的实现可能会缓存所有 char 和 short 值,以及 -32K 到 +32K 范围内的 int 和 long 值.
Less memory-limited implementations might, for example, cache all char and short values, as well as int and long values in the range of -32K to +32K.
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