我有 1100、1002、1022 等数字.我想要单独的数字,例如对于第一个数字 1100,我想要 1、1、0、0.
I have numbers like 1100, 1002, 1022 etc. I would like to have the individual digits, for example for the first number 1100 I want to have 1, 1, 0, 0.
如何在 Java 中获得它?
How can I get it in Java?
为此,您将使用 %
(mod) 运算符.
To do this, you will use the %
(mod) operator.
int number; // = some int
while (number > 0) {
print( number % 10);
number = number / 10;
}
mod 运算符将为您提供对数字进行 int 除法的余数.
The mod operator will give you the remainder of doing int division on a number.
所以,
10012 % 10 = 2
因为:
10012 / 10 = 1001, remainder 2
注意: 正如 Paul 所说,这会以相反的顺序为您提供数字.您需要将它们压入堆栈并以相反的顺序将它们弹出.
Note: As Paul noted, this will give you the numbers in reverse order. You will need to push them onto a stack and pop them off in reverse order.
按正确顺序打印数字的代码:
Code to print the numbers in the correct order:
int number; // = and int
LinkedList<Integer> stack = new LinkedList<Integer>();
while (number > 0) {
stack.push( number % 10 );
number = number / 10;
}
while (!stack.isEmpty()) {
print(stack.pop());
}
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