我正在尝试使用 Powermock 和 Mockito 来模拟 void 静态方法来抛出异常,如下所示.但是我遇到了一个问题.除非我使用相同的参数对 Adder.add() 进行两次调用,否则不会抛出模拟的 IOException
.
I am trying to use Powermock and Mockito to mock a void static method to throw exception as below. But I met a problem. Unless I make the two invocations of Adder.add() with the same argument, the mocked IOException
won't be thrown.
顺便说一句,我已将 @RunWith(PowerMockRunner.class)
和 @PrepareForTest(Adder.class)
添加到单元测试类中.
BTW, I've added @RunWith(PowerMockRunner.class)
and @PrepareForTest(Adder.class)
to the unit test class.
class Adder{
public static void add(int i) throws IOException{
return;
}
}
@Test
public void testAdder() throws IOException{
PowerMockito.mockStatic(Adder.class);
PowerMockito.doThrow(new IOException()).when(Adder.class);
Adder.add(12);
try {
Adder.add(11);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// assert things
}
提前致谢.:)
答案如下.
在这里咨询后http://code.google.com/p/powermock/issues/detail?id=278 ,其实上面的 Adder.add(12) 就是设置 mock 静态方法的一部分.这意味着当使用参数 12 调用 Adder.add() 时,将抛出 IOException.这很难理解,对吧?:) 所以应该写成下面这样.
After consulting here http://code.google.com/p/powermock/issues/detail?id=278 , in fact Adder.add(12) above is part of setting up mock static method. It means when invoking Adder.add() with argument 12, IOException will be thrown. It is hard to understand, right? :) So it should be written as below.
PowerMockito.mockStatic(Adder.class);
PowerMockito.doThrow(new IOException()).when(Adder.class);
Adder.add(anyInt());
答案如下.
在这里咨询后http://code.google.com/p/powermock/issues/detail?id=278 ,其实上面的 Adder.add(12) 就是设置 mock 静态方法的一部分.这意味着当使用参数 12 调用 Adder.add() 时,将抛出 IOException.这很难理解,对吧?:) 所以应该写成下面这样.
After consulting here http://code.google.com/p/powermock/issues/detail?id=278 , in fact Adder.add(12) above is part of setting up mock static method. It means when invoking Adder.add() with argument 12, IOException will be thrown. It is hard to understand, right? :) So it should be written as below.
PowerMockito.mockStatic(Adder.class);
PowerMockito.doThrow(new IOException()).when(Adder.class);
Adder.add(anyInt());
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