我想解析一个日期.我的字符串日期是Thu Jan 19 2012 08:00 PM".我要解析的代码是:
I would like to parse a date. My String date is "Thu Jan 19 2012 08:00 PM". And my code to parse is:
format = new SimpleDateFormat("EEE MMM dd yyyy hh:mm aaa");
this.settDate(new Timestamp((format.parse(sDate)).getTime()));
但是,它不起作用.我如何解析这个日期?
However, it does not work. How could I parse this date?
完整的方法是:
public void saveTask(int iDevice, String description, String sDate) throws ParseException {
format = new SimpleDateFormat("EEE MMM dd yyyy hh:mm aaa");
this.setiDeviceId(iDevice);
this.setsDescription(description);
this.settDate(new Timestamp((format.parse(sDate)).getTime()));
DatabaseManager.save(this);
}
还有例外:
java.text.ParseException: Unparseable date: "Thu Jan 19 2012 01:00 AM"
调试图片:
谢谢!
试试下面的代码... 测试成功
Try below code... Tested and worked
String dateStr = "Thu Jan 19 2012 01:00 PM";
DateFormat readFormat = new SimpleDateFormat( "EEE MMM dd yyyy hh:mm aaa");
DateFormat writeFormat = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss");
Date date = null;
try {
date = readFormat.parse( dateStr );
} catch ( ParseException e ) {
e.printStackTrace();
}
String formattedDate = "";
if( date != null ) {
formattedDate = writeFormat.format( date );
}
System.out.println(formattedDate);
输出为 2012-01-19 13:00:00
干杯!!!乐于助人!!!
Cheers!!! Happy to help!!!
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