2字节短java

问题描述

我正在从串行端口读取 133 个长度的数据包，最后 2 个字节包含 CRC 值，2 个字节值我使用 java 制作单个(我认为是短的).这就是我所做的，

i'm reading 133 length packet from serialport,last 2 bytes contain CRC values,2 bytes value i've make single(short i think) using java. this what i have done,

short high=(-48 & 0x00ff);
short low=80;

short c=(short) ((high<<8)+low);

但我没有得到正确的结果，是因为签名值有问题吗?我该如何解决这个问题，请帮助我遇到麻烦

but i'm not getting correct result,is it problem because signed valued? how can i solve this problem,plz help me i'm in trouble

推荐答案

请记住，如果您对细节不太熟悉，则不必为位移而纠结.您可以使用 ByteBuffer 来帮助您:

Remember, you don't have to tie yourself in knots with bit shifting if you're not too familiar with the details. You can use a ByteBuffer to help you out:

ByteBuffer bb = ByteBuffer.allocate(2);
bb.order(ByteOrder.LITTLE_ENDIAN);
bb.put(firstByte);
bb.put(secondByte);
short shortVal = bb.getShort(0);

反之亦然，你可以先放一个短，然后再拉出字节.

And vice versa, you can put a short, then pull out bytes.

顺便说一下，按位运算会自动将操作数提升到至少一个 int 的宽度.真的没有不允许将一个字节移动超过 7 位"的概念以及其他似乎正在流传的谣言.

By the way, bitwise operations automatically promote the operands to at least the width of an int. There's really no notion of "not being allowed to shift a byte more than 7 bits" and other rumours that seem to be going round.

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