将文本文件读入Java中的char数组

问题描述

我正在读取一个文本文件并尝试将它逐个字符地存储到一个数组中.我的方法(如下)预先定义了一个初始长度为 100000 的 char 数组(我的主要问题在这里).因此，如果文件包含的字符少于该数量(如果字符多于该数量，也会出现问题)，那么我的数组中有空值.我想避免这种情况.有没有办法预先确定文本文件中存在的字符数量?还是有更好的方法来按字符存储文件?

I am reading a text file and trying to store it into an array char by char. My approach (below) pre-defines a char array with an initial length of 100000 (my main issue here). So, if the file contains characters less than that amount (problem also if more characters than that), then there are nulls in my array. I want to avoid that. Is there a way to predetermine the amount of characters present in a text file? Or is there a better approach altogether to store the file char by char?

char buf[] = new char[100000];
FileReader fr = new FileReader(filename);
BufferedReader br = new BufferedReader(fr);
br.read(buf);
for(int i = 0; i < buf.length; i++)
{
     //Do stuff here
}

推荐答案

使用 ArrayList of Characters 来接受值.之后将 ArrayList 转换为 Array 为

Use an ArrayList of Characters to accept the values. After that convert ArrayList to an Array as

 char[] resultArray = list.toArray(new char[list.size()]);

您应该使用 br.readLine() 而不是 br.read()，如下所示:

You should use br.readLine() instead of br.read() as follows:

String str;
while((str = br.readLine())!=null){
        str.tocharArray();
}

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