我需要 unmarshall 未知 XML 内容的子集,使用该未编组的对象,我需要修改一些内容并重新绑定相同的 XML 内容(子集) 与原始 XML.
I have a requirement to unmarshall a subset of Unknown XML content, with that unmarshalled object, I need modify some contents and re-bind the same XML content(subset) with the Original XML.
输入 XML 示例:
<Message>
<x>
</x>
<y>
</y>
<z>
</z>
<!-- Need to unmarshall this content to "Content" - java Object -->
<Content>
<Name>Robin</Name>
<Role>SM</Role>
<Status>Active</Status>
</Content>
.....
</Message>
需要单独解组 <Content> 标记,保持其他 XML 部分相同.需要修改<Content>标签中的元素,并将修改后的XML部分与原文绑定,如下图:
Need to unmarshall the <Content> tag alone, by keeping the other XML part as same. Need to modify the elements in <Content> tag and bind the modified XML part with the original as shown below:
预期输出 XML:
<Message>
<x>
</x>
<y>
</y>
<z>
</z>
<!-- Need to unmarshall this content to "Content" - java Object -->
<Content>
<Name>Robin_123</Name>
<Role>Senior Member</Role>
<Status>1</Status>
</Content>
.....
</Message>
我的问题:
此要求的可能解决方案是什么?(除了 DOM 解析 - 因为 XML 网络非常庞大)
What is the possible solution for this Requirement ? (Except DOM parsing - as XML contnet is very huge)
JAXB2.0 中是否有任何选项可以执行此操作?
Is there any option to do this in JAXB2.0 ?
请就此提出您的建议.
考虑使用 StAX API.
对于给定的示例,此代码使用 Content 元素的根元素创建一个 DOM 文档:
For the given sample, this code creates a DOM document with a root element of the Content element:
class ContentFinder implements StreamFilter {
private boolean capture = false;
@Override public boolean accept(XMLStreamReader xml) {
if (xml.isStartElement() && "Content".equals(xml.getLocalName())) {
capture = true;
} else if (xml.isEndElement() && "Content".equals(xml.getLocalName())) {
capture = false;
return true;
}
return capture;
}
}
XMLInputFactory inFactory = XMLInputFactory.newFactory();
XMLStreamReader reader = inFactory.createXMLStreamReader(inputStream);
reader = inFactory.createFilteredReader(reader, new ContentFinder());
Source src = new StAXSource(reader);
DOMResult res = new DOMResult();
TransformerFactory.newInstance().newTransformer().transform(src, res);
Document doc = (Document) res.getNode();
这可以是 作为 /transform/dom/DOMSource.html" rel="nofollow">DOMSource.
This can then be passed to JAXB as a DOMSource.
在输出时重写 XML 时可以使用类似的技术.
Similar techniques can be used when rewriting the XML on output.
JAXB 似乎不直接接受 StreamSource,至少在 Oracle 1.7 实现中是这样.
JAXB doesn't seem to accept a StreamSource directly, at least in the Oracle 1.7 implementation.
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