如何解码/获取文件编码(Power BI 桌面文件)

问题描述

我正在尝试解码 Power BI 桌面报表 (pbix) 内部文件 (DataMashup).我的目标是使用任何编程语言创建 Power-BI 桌面报表、数据模型.我使用 Java 作为初始值.

I am having power BI desktop report(pbix) internal file (DataMashup), which i am trying to decode. My Aim is to create Power-BI desktop report, Data Model using any programming language. I am using Java for initial.

文件使用某种编码技术进行编码.

files are encoded with some encoding technique.

我尝试获取文件的编码，它返回 windows 1254.但没有进行解码.

I tried to get encoding of file and it is returning windows 1254. but decoding is not happening.

File f = new File("example.txt");

    String[] charsetsToBeTested = {"UTF-8", "windows-1254", "ISO-8859-7"};

    CharsetDetector cd = new CharsetDetector();
    Charset charset = cd.detectCharset(f, charsetsToBeTested);

    if (charset != null) {
        try {
            InputStreamReader reader = new InputStreamReader(new FileInputStream(f), charset);
            int c = 0;
            while ((c = reader.read()) != -1) {
                System.out.print((char)c);
            }
            reader.close();
        } catch (FileNotFoundException fnfe) {
            fnfe.printStackTrace();
        }catch(IOException ioe){
            ioe.printStackTrace();
        }

    }else{
        System.out.println("Unrecognized charset.");
    }

文件解压也不行

public void unZipIt(String zipFile, String outputFolder)
{
    byte buffer[] = new byte[1024];
    try
    {
        File folder = new File(outputFolder);
        if(!folder.exists())
        {
            folder.mkdir();
        }
        ZipInputStream zis = new ZipInputStream(new FileInputStream(zipFile));
        System.out.println(zis);

        System.out.println(zis.getNextEntry());
        for(ZipEntry ze = zis.getNextEntry(); ze != null; ze = zis.getNextEntry())
        {
            String fileName = ze.getName();
            System.out.println(ze);
            File newFile = new File((new StringBuilder(String.valueOf(outputFolder))).append(File.separator).append(fileName).toString());
            System.out.println((new StringBuilder("file unzip : ")).append(newFile.getAbsoluteFile()).toString());
            (new File(newFile.getParent())).mkdirs();
            FileOutputStream fos = new FileOutputStream(newFile);
            int len;
            while((len = zis.read(buffer)) > 0) 
            {
                fos.write(buffer, 0, len);
            }
            fos.close();
        }

        zis.closeEntry();
        zis.close();
        System.out.println("Done");
    }
    catch(IOException ex)
    {
        ex.printStackTrace();
    }
}

推荐答案

您可以使用 System.IO.Packaging 库来提取 Power BI 数据混搭.它使用 OPC 封装标准，请参阅 这里.

You can use the System.IO.Packaging library to extract the Power BI data mashup. It uses the OPC package standard, see here.

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